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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,454 of 10,432    |
|    Dr Huang to asetof...@gmail.com    |
|    Re: [Axiom] define a rule    |
|    06 Jun 17 21:08:35    |
      From: drhuang57@gmail.com              On Sunday, 4 June 2017 02:58:19 UTC+10, asetof...@gmail.com wrote:       > I defined the follow rule in Axiom       >       > r:=rule(j*j==1)       >       > But in only this case found one not expected result       >       > r(-1+(j*j))       >       > return 1 instead of 0       > All other number I tried in the place of -1 are ok       >       > Where is the error?              It is easy to define rule in mathHandbook.com, e.g define integrate rule:       integrate(x_^n_,x_):=if(n== -1, log(x),x^(n+1)/(n+1))                     reference math handbook       www.mathHandbook.com              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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