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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,455 of 10,432    |
|    asetofsymbols@gmail.com to All    |
|    Re: [Axiom] define a rule    |
|    07 Jun 17 02:58:11    |
      On       ------       What about this:       One expression       f(x1,...,xn)              One rule on f(x1...xn)       If (x1,...,xn)in B then        substitute f(x1..xn) with g       Else do nothing       ------       I find a way for doing above       it use one function       predicate: Expression Float -> Boolean       predicate(x)==(not integer?(x)=> false;       and the necessary conversion x::INT              and rule defined using       (y|predicate(y))              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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