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   sci.math.symbolic      Symbolic algebra discussion      10,432 messages   

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   Message 9,455 of 10,432   
   asetofsymbols@gmail.com to All   
   Re: [Axiom] define a rule   
   07 Jun 17 02:58:11   
   
   On   
   ------   
   What about this:   
   One expression   
   f(x1,...,xn)   
      
   One rule on f(x1...xn)   
   If (x1,...,xn)in B then   
        substitute f(x1..xn) with g   
   Else do nothing   
   ------   
   I find a way for doing above   
   it use one function   
   predicate: Expression Float -> Boolean   
   predicate(x)==(not integer?(x)=> false;   
   and the necessary conversion x::INT   
      
   and rule defined using   
   (y|predicate(y))   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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