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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,649 of 10,432    |
|    Nasser M. Abbasi to clicliclic@freenet.de    |
|    Re: fyi, new build of CAS integration te    |
|    04 Oct 17 11:38:37    |
      From: nma@12000.org              On 10/4/2017 11:21 AM, clicliclic@freenet.de wrote:              > I believe that:       >       > SQRT(x^2/(1 + SQRT(x^2 - 1))^2)*(1 + SQRT(x^2 - 1))/x = x/SQRT(x^2)       >       > FriCAS will probably squeal, but can Mathematica or Maple validate or       > invalidate this simplification?       >       > Martin.       >              fyi;              Mathematica says, for real x, the above is valid only for x<=1 || x>=1              In[1]:= expr1 = Sqrt[x^2/(1 + Sqrt[x^2 - 1])^2]*((1 + Sqrt[x^2 - 1])/x);       In[2]:= expr2 = x/Sqrt[x^2];       In[5]:= Reduce[expr1 - expr2 == 0, x, Reals]              Out[5]= x <= -1 || x >= 1              --Nasser              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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