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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,651 of 10,432    |
|    Albert Rich to clicl...@freenet.de    |
|    Re: fyi, new build of CAS integration te    |
|    05 Oct 17 03:00:50    |
      From: Albert_Rich@msn.com              On Wednesday, October 4, 2017 at 6:21:59 AM UTC-10, clicl...@freenet.de wrote:              > I believe that:       >       > SQRT(x^2/(1 + SQRT(x^2 - 1))^2)*(1 + SQRT(x^2 - 1))/x = x/SQRT(x^2)       >       > FriCAS will probably squeal, but can Mathematica or Maple validate or       > invalidate this simplification?       >       > Martin.              3D plots of the absolute value of the difference of the two sides of the       equation with x replaced by x+y i over various ranges of x and y indicates       your belief is probably correct.              However, I hesitate to have Rubi return               x/Sqrt[x^2]*EllipticF[2*ArcTan[(x^2-1)^(1/4)],1/2]              as the optimal antiderivative of 1/(x^2-1)^(3/4) since the host CAS cannot       verify it correct. But I will certainly put it in the code as a comment.              Albert              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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