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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,792 of 10,432    |
|    Nasser M. Abbasi to clicliclic@freenet.de    |
|    Re: More teething help    |
|    28 Jan 18 02:59:47    |
      From: nma@12000.org              On 1/28/2018 2:27 AM, clicliclic@freenet.de wrote:              > In terms of a, the three solutions correspond to the integrals:       >       > INT((x + a)/((x - a)*SQRT(x^3 - x^2*(a^2 + 1) + a^2*x)), x)       >       > INT((x + a - 2)       > /((x - a)*SQRT(x^3 + x^2*(a^2 - 2*a - 1) + a*x*(2 - a))), x)       >       > INT((x*(2*a - 1) - a)       > /((x - a)*SQRT(x^3*(2*a - 1) - x^2*(a^2 + 2*a - 1) + a^2*x)), x)       >       > I am confident that FriCAS can solve all three,              fyi,              The third one gives Fricas some trouble              ii:=integrate((x*(2*a - 1)-a)/((x - a)*sqrt(x^3*(2*a - 1)-x^2*(a^2 + 2*a - 1)       + a^2*x)), x)               >> Error detected within library code:        catdef: division by zero              But the strange thing, if I run it again, it works second time              ii:=integrate((x*(2*a - 1)-a)/((x - a)*sqrt(x^3*(2*a - 1)-x^2*(a^2 + 2*a - 1)       + a^2*x)), x)       log(((-2)*((2*a+(-1))*x^3+((-1)*a^2+(-2)*a+1)*x^2+a^2*x)^(1/2)+(x^2+(2*a+(-2        ))*x+(-1)*a^2))/(x^2+(-2)*a*x+a^2))              And if I run again I get division by zero. Again, it works, and so on.       It seems memory stored internally affect the result.              Very strange. I need to post this at Fricas forum.              Fricas 1.3.2 on Linux.              >and suspect that there       > are no other (i.e. non-Goursat) pseudo-elliptics of this general form.       > By the way, a rule-based integrator would not need to solve polynomial       > equations, it only needs to check if a given instance of the integrand       > satisfies them.       >       > Martin.       >              --Nasser              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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