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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,961 of 10,432    |
|    Albert Rich to clicl...@freenet.de    |
|    Re: arc tangent doubling revisited    |
|    13 Jul 19 02:30:24    |
      From: Albert_Rich@msn.com              On Tuesday, July 9, 2019 at 6:12:16 AM UTC-10, clicl...@freenet.de wrote:       >       > integrate((x - sqrt(a^2 + 1) - a)/       > ((x + sqrt(a^2 + 1) - a)*sqrt((x - a)*(x^2 + 1))), x)              Factoring out the piecewise-constant sqrt(x-a)*sqrt(x^2+1)/sqrt((x-a)*(x^2+1))       and making the substitution t=sqrt(x-a), transforms this into a        seudo-elliptic integrand of the form               (A+B*x^2)/((d+e*x^2)*sqrt(a+b*x^2+c*x^4))              where c*d^2-a*e^2=0 and B*d+A*e=0. That Rubi knows how to integrate by       transforming it into an elementary integrand of the form 1/(C+D*t^2) using the       substitution t=x/sqrt(a+b*x^2+c*x^4).              Albert              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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