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|    sci.math.symbolic    |    Symbolic algebra discussion    |    10,432 messages    |
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|    Message 9,975 of 10,432    |
|    Nasser M. Abbasi to Nasser M. Abbasi    |
|    Re: question on an integral from CAS int    |
|    16 Oct 19 02:19:31    |
      From: nma@12000.org              On 10/16/2019 2:07 AM, Nasser M. Abbasi wrote:       >       > Btw, this the same with the original identity       >       > 2*pi*SQRT(1 - z) at z=0 is zero, but       > SQRT(z - 1)*(2*LN(- SQRT(z - 1)) - LN(z - 1)) at z=0 is indeterminant       > because of the 0*(-infinity - infinity) term that shows up above when z=0.       >              opps, I meant at z=1 in the above, not z=0.              --Nasser              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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