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   sci.math.symbolic      Symbolic algebra discussion      10,432 messages   

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   Message 9,975 of 10,432   
   Nasser M. Abbasi to Nasser M. Abbasi   
   Re: question on an integral from CAS int   
   16 Oct 19 02:19:31   
   
   From: nma@12000.org   
      
   On 10/16/2019 2:07 AM, Nasser M. Abbasi wrote:   
   >   
   > Btw, this the same with the original identity   
   >   
   > 2*pi*SQRT(1 - z) at z=0 is zero, but   
   > SQRT(z - 1)*(2*LN(- SQRT(z - 1)) - LN(z - 1)) at z=0 is indeterminant   
   > because of the 0*(-infinity - infinity) term that shows up above when z=0.   
   >   
      
   opps, I meant at z=1 in the above, not z=0.   
      
   --Nasser   
      
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