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|    sci.optics    |    Discussion relating to the science of op    |    12,750 messages    |
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|    Message 11,039 of 12,750    |
|    Ron Gibbs to All    |
|    Re: PSF    |
|    12 Jan 12 10:16:25    |
      c50ebd2e       From: ron@gibbsassociates.co.uk              "Michael Koch" wrote in message       news:7605e3a1-dba5-4d2d-b3db-f0ff5d7d7b2f@s18g2000vby.googlegroups.com...              Hi,              let's assume we know the wavefront error (phase map) of an optical       system, for example a parabolical mirror. We know the phase for each       point on the surface, or with other words we know all Zernike       coefficients. With these input data it's possible to calculate the       PSF.       Question: Is the PSF equivalent to the image of a star, taken with       this optical system? Or is the PSF only based on wave optics, while       geometrical optical effects (transversal abberations) are neglected?              Michael              By definition, PSF is the star image. I guess your question relates to       calculation of PSF from Zernikes. In Zemax, there are several ways of       modelling a surface using Zernike coefficients, and PSF is accurately       calculated using FFT (quicker) or Huygens (more accurate in some       circumstances), taking into account aberrations and diffraction. I don't see       the problem.              Ron       www.gibbsassociates.co.uk              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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