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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 15,557 of 17,516    |
|    Jos Bergervoet to John Heath    |
|    Re: Centripetal force in Special Relativ    |
|    15 Feb 17 08:44:35    |
      From: jos.bergervoet@xs4all.nl              On 2/12/2017 5:27 PM, John Heath wrote:       > On Thursday, December 29, 2016 at 11:21:45 AM UTC-5, Jos Bergervoet wrote:       >> On 12/29/2016 8:59 AM, John Heath wrote:        ...        ...       >>> Two wires from floor to ceiling 1 inch apart with current moving up in       >>> both wires. The force is attractive.       >>       >> Exactly, that's magnetic force. And the electric force       >> between the parallel moving charges (the electrons) is       >> repulsive, so that's the opposite.       >>       >>> There are as many electrons as       >>> there are protons in the copper wire. As current starts to flow up in       >>> both wires the electrons see the other electron as non relativistic as       >>> they are both moving up . However the electrons see the protons as       >>> length contracted therefore there is and attractive Coulomb force       >>> between the wires.       >>       >> You now have stationary particles in addition to the       >> parallel moving charges. The electric force between the       >> moving charges is still repulsive and my only claim       >> was that that one is opposite to the magnetic force!       >       > I wish this exchange of ideas were closer to 900 MHz vs 2.4 GHz as I       > could use some help in this area. I suspect you feel my pain.              Actually I might be missing your exact point (why not consider       5.8GHz?)              But we certainly can look at the two currents for these       frequencies. There are basically two situations to look at:        1) We could consider currents without phase delay over the       whole length of two long parallel wires. The analog of       parallel or anti-parallel static currents would be       in-phase alternating currents or 180 degrees out-of-phase       currents, in both cases changing direction simultaneously       everywhere along the length of the wires. (In practice this       is not a behavior that is easy to create!)        2) We could have waves propagating over the wires, again       with the currents either in-phase or 180 deg. out of phase,       and with the waves moving in the same direction. (This is       the more natural situation in a transmission line.)               In case 1) the fields of each wire can be expressed in       Hankel functions of the radial distance to the wire, at       small distances equal to the 1/r fields of the static case.       So with increasing distance between the wires, the case with       attractive force for DC currents (equal-direction currents)       will turn into repulsive force and then back to attractive       (and in between also alternating forces with the double       frequency of the current!). There are no unbalanced charges       in the wires so we have no radial E-fields, the only force is       from the B-field.               In case 2) we basically have the two-wire transmission       line. Opposite currents require the differential-mode       solution for the signal, in-phase currents the common-mode       solution. These are both approximately TEM solutions (the       common-mode solution only very approximately) which means       that: a) the fields are shaped more or less like static       fields, and b) the forces from radial E-fields and from       the B-fields now approximately cancel each other. The latter       follows from the fact that d rho/dt = dI/dx, the continuity       equation for the charge. This gives equal charges where       there are equal currents (current and voltage are in phase       in a transmission line) and as we saw above: that means       opposite electric and magnetic forces! That they are also       (approximately) equal in magnitude is easy to verify from       the equations.              So, at RF frequencies, with transmission line behavior of       the currents, the force is substantially smaller than for       a pure DC current (without voltage). Of course if you add       a DC voltage as well (with the ratio to the current equal       to the characteristic impedance of the transmission line)       then you will have the same cancellation for DC as well.              --       Jos              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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