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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 15,578 of 17,516    |
|    rockbrentwood@gmail.com to stargene    |
|    Re: Does all Hawking radiation require a    |
|    01 Mar 17 21:40:05    |
      [Moderator's note: Please avoid sending long lines, intentionally or       otherwise. We do what we can to translate garbled stuff to the format       of a text-only group, but our resources are limited, thus the "=" signs       below. -P.H.]              On Wednesday, February 22, 2017 at 2:08:07 PM UTC-6, stargene wrote:       > This immense grav'l field, at r, should display a strong Unruh effect,       > in an accelerating frame, -- I assume with its own spectrum of virtual       > particles.              [Remainder of description deleted]              The foregoing is why Hawking rejected the idea of there ever being a real       honest-to-goodness event horizon.              A more fundamental, little-noted-as-such, problem exists with the whole mat=       ter. Prior to the Kruskal theorem, the understanding of black holes or (mor=       e generally) the Schwarzschild solution was that there was some kind of sin=       gularity at the event horizon.              What the Kruskal theorem did -- by the folklore account -- is that it "remo=       ved" this singularity by showing that it was "only" a "coordinate singulari=       ty". What it ACTUALLY did was something far worse: it provided an embodimen=       t of the expression "out of the frying pan into the fire" by replacing what=        had henceforth been "only" a coordinate singularity by an ACTUAL singulari=       ty!              "Singularities" are simply a polite way of saying "contradiction". So, the =       usual folklore account (buttressed by such results as the Information Parad=       ox) is then that there is something wrong with ALL classical geometry and t=       hat a solution to this predicament must be found in quantum theory.              That argument is a fallacy -- and those who pose it either know so or ought=        to know better. All quantum theories, no matter how construed, have the pr=       operty that they reflect a classical theory ... not approximately but exact=       ly. In particular, the coherent states of the theory ARE the classical stat=       es of the corresponding classical theory, the difference being that the coh=       erent states have non-zero overlap, while the classical states do not.              A quantum theory that includes the phenomenon of gravity within its scope M=       UST possess a classical geometry of some form or another in the form of its=        coherent states. So, for instance, when you hear mention about how this or=        that framework (be it Loop Quantum [sic] Gravity or String Theory) embodie=       s gravity in a quantum setting, the first question you should ask is: what =       are its coherent states? If you don't get or find a clear reply, then you k=       now that the formalism is ill-conceived, ill-founded or both (no matter how=        many research papers might be written on it in Phys. Rev.).              So, there is no getting away from classical geometry, period.              Thus, when you have a result like the Kruskal Theorem -- which replaces a s=       ignificant but relatively harmless "coordinate" singularity by an ACTUAL si=       ngularity -- this result show NOT that classical geometry has a problem, bu=       t rather that RIEMANNIAN (and Riemann-Cartan) geometry does!              In particular, the premise that the signature of the metric remains the sam=       e, and that the metric is everywhere non-degenerate.              There is, in fact, a small set of literature out there that treats the even=       t horizon (and similarly that would treat Hubble Horizons or "Big Rips") as=        an actual signature-changing surface -- much as Hawking did (albeit in gui=       se as a "technical expedient") in his first treatments of Black Hole thermo=       dynamics. This research, in effect, gives physicality to the "Euclideanizat=       ion" trick that Hawking used in formulating his semi-classical semi-quantum=        black hole physics. The event horizon is then a boundary to a Euclidean wo=       rmhole. That term is what you'll find links to in research archives if you =       do a search.              The passing over from a Lorenzian background (where the Poincare' group hol=       ds sway locally) to a Euclidean background (where the 4D Euclidean group ho=       lds sway locally) takes place through a c -> 0 intermediate boundary. This =       would locally be covered by what's known as the "Carroll Group" (the c = =       0 limit of Poincare') or even the "Static Group" (the "c = 0" limit of Ga=       lilei, yes there is such a thing!) The passing over, in terms of the kinema=       tic groups, is a group contraction from Poincare' to Carroll and then throu=       gh Carroll to Euclid 4D.              More generally, another possible way to pass over to Euclid can then be ent=       ertained: Poincare' -> Galilei -> Euclid. The boundary, here would be a sur=       face on which c = infinity which (from the point of view of the Relativis=       t) would be called a "null hypersurface". That pretty much characterizes th=       e Cosmological Horizon and the 3-surface at "time 0" that it sits on. Acros=       s that boundary (according to Hawking) is a Euclidean domain. Here, too, yo=       u will find research that has given physicality to this "technical fix" of =       Hawking.              The two routes toward Euclideanization (or three if you count the passing t=       hrough the Static Group) are DISTINCT ways of getting from Poincare' to Euc=       lid, but are conflated and not even recognized as distinct in formalisms li=       ke the Path Integral approach (where the assumption isn't even given physic=       ality or treated as anything but a "technical fix"!)              >       > My naive question then is: Could one member of such a virtual pair       > then still become relatively isolated from its partner, if it momentarily       > travels toward M, feeling a much higher potential, while its partner       > moves slightly outward from M, into a lower potential.       >       > Could the local field potential differences, in the neighborhood of r,       > then mediate a non-zero chance of the latter member escaping and       > becoming real at infinity?       >       > Ie: A sort of proto-Hawking radiation?       >       > Or does any and all chance of some of the Unruh field of particles       > becoming real require the prior existence of the actual even horizon?       >       > Thanks,       > Gene              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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