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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 15,590 of 17,516    |
|    Roland Franzius to All    |
|    Re: How to measure a Lorentz contraction    |
|    09 Mar 17 10:39:07    |
      From: roland.franzius@uos.de              Am 08.03.2017 um 09:09 schrieb John Heath:       > On Sunday, March 5, 2017 at 2:55:56 AM UTC-5, Roland Franzius wrote:       >> Am 03.03.2017 um 10:04 schrieb John Heath:       >>> I like it. Simple and do-able. Should       >>> be able to swing a 3 foot wire at 3 or       >>> 4 Hz by hand with the hand end of the       >>> wire clamped to a scope. I have spectrum       >>> lab audio analyzer software on a lap top       >>> for VLF whistlers , moving sky charges.       >>> With this most of what is needed is already       >>> in place. As you have already done this I       >>> can proceed with confidence. One concern.       >>> Standing in the middle of no where spinning       >>> a 3 foot wire while looking at a lap top could       >>> draw unwanted attention. I am tested for       >>> a better WIFI connection officer , that's       >>> my story and I am sticking to it.       >>>       >>> As to your dislike of the Lorentz contraction       >>> interpretation of magnetism you are not alone.       >>> I can say from my shoes it grows on you       >>> over time. How often is there an opportunity       >>> to toss a fundamental force in nature such       >>> as magnetism straight into the trash bin?       >>> One less to worry about.       >>>       >>       >>       >> Don't, because there are genuine electric and magnetic fields.       >>       >> The two quadratic forms E^2-B^2 and E.B are invariant with respect to       >> Lorenz transformations. E.B=0 and |E|=|B| is mainly radiation.       >>       >> So there are static fields with |E|>|B| which are predominantly electric       >> fields because you can find a system of reference with B'=0 and E' =       >> E/sqrt(1-(v/c)^2).       >> This system can be thought to be the rest system where you see charges       >> at rest producing their common Coulomb field.       >>       >> And there are predominantly magnetic fields |B|>|E| where you can find a       >> system reference with E'= 0 and B' = B/sqrt(1-(v/c)^2)       >>       >> Taken cum grano salis of course, because E,B are components of a rank 2       >> tensor field, transforming with the product of two Lorentz tranformation       >> matrices.       >>       >> An example of pure magnetic field with E=0 everywhere is the cylindrical=       >>       >> magnetic field B_phi =1/r around a finite conducting wire with with two       >> equal constant currents: one of the negative charges to the left and       >> positive charges to the right of identical current and charge density.       >>       >> So as an experiment, move at constant speed with your synchronized       >> clocks/meterstick/ampere-meter/volt-meter equipment along a wire with       >> the half velocity v/2 of the electron current.       >>       >> Now you have two equal currents of negative electrons and positive ions       >> with equal but opposite velocities +-v/2.       >>       >> The wire is assumed somehow to be electrical neutral in the rest system       >> of the ions.       >>       >> Of course, there will be a small longitudinal electrical field E_z to       >> drive the electric current against the resistivity and to supply by ExB       >> the dissipation energy current density from the field outside into the       >> wire.       >>       >> E_z and dissipation can be made very small or even zero for a       >> superconductor. So we can neglect the dissipation problem in a first       >> approximation.       >>       >> Now you have by the Lorenz formula       >>       >> B'_phi = B_phi /Sqrt(1-(v/2c)^2)       >>       >> and       >>       >> E'_r = v/(2c) x B_phi / Sqrt(1-(v/2c)^2)       >>       >> which means that in this system the current is larger and the wire is       >> not neutral but - as an ideal conductor - carries some surface charge       >> density D_r that, by definition, is the value of D_r at the surface.       >>       >> How does this happen?       >>       >> Lorentz contraction contracts the longitudinal measured distance of the       >> ions from rest at v=0 to v/2 using the simultaneity of the moving       >> clocks. By the same argument the distance of electrons is enlarged       >> because their velocity is reduced from v to v/2. So the net charge       >> density varies linearly with v.       >>       >> This fundamental effect arises at velocities as small as the current       >> velocity of electrons of order 10^-11 lightseconds/second for a current       >> of 1 A at a density of some 10^27 m^-3.       >>       >> The gigantic particle density of charges moving freely in metallic       >> conductors makes these macroscopic effects easily detectable and       >> measureable with high precision. This simple fact enabled Gau=DF, Faraday       >> Maxwell and Einstein to find the laws of electrodynamics.       >> These laws, applied by the gauge of the 4-momentum, imply Lorentz       >> invariance of all physical laws.       >>       >> --       >>       >> Roland Franzius       >       > Yes there is B=0 E=1 such as a Van De Graaff generator. There       > is also B=1 E=0 such as a magnet. I will give an example in       > applied physics where the same magnet is B=0 E=1.       >       > This experiment requires a budget of 20 dollars plus a cleared       > kitchen table. 1 old school small black and white TV set from       > a thrift shop , 5 to 10 bucks , and a strong flat coin type       > magnet from a hobby shop 10 to 15 bucks. We now have our       > electron particle accelerator , TV , with a phosphor screen       > to collect electron trajectory data. Electron velocity is in       > the neighborhood of .1 c for a accelerating element of 10 KV       > for this type of TV. Place the north end of the magnet facing       > the TV screen. You will note the screen raster will turn       > clockwise , Maxwell is right. Place the south pole and the       > screen will turn counter clockwise , Maxwell is still right.       > So far we have B=1 E=0. However if you look closely at the       > magnet from the side you will see a black spot. A spot where       > electrons with a velocity of .1 c are not hitting the phosphor?       > Turning the magnet around will not help as there will still be       > a black spot that electron do not care for. A Coulomb force to       > cause this would have to be in the range of 15 KV to stop an       > electron at .1 c in its tracks. That coulomb force is not in       > Maxwell's equations. However it is in the Lorentz contraction       > interpretation where effective movement of electrons only in       > a magnet will result in a negative Coulomb force. This makes       > it B=0 E=1 for a magnet.       >       > Interesting though. If it were a anti matter magnet then it       > would be the positrons that are effectively moving therefore       > a strong positive Coulomb force. The black spot would now be       > brighter than the rest of the screen. Now that I think of it       > the screen plus a 10 city block radius around the screen would       > light up. Maybe moving protons to make the positive magnet       > would be better.       >       >                     The black spot is the shielding effect of the magentic vector potential       of the magnetic field. It is the cause of a centrifugal potential,       simply said.              The kinetic energy equation in a static magnetic field is       H = 1/2 ( p-e/c A(x))^2              The B-field on the axis       B = B_0 f(z,r) e_z              Transformed to cylinder coordinates and written as an antisymmetric rank       2 tensor field of flux density through areas dr /\ dphi of the planes       perpendicular the z-axis              F = B_0 f(z,r) dr /\ dphi              To have div B=0 with this ansatz we must have dF=0-> d/dz f(z,r)=0.                     [continued in next message]              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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