From: hitlong@yahoo.com   
      
   On Friday, May 26, 2017 at 1:23:55 AM UTC-6, John Heath wrote:   
   >   
   > I am going to make a cannon to test Newtonian physics. The cannon will   
   > consist of gun powder and a cannon ball. The mass of the cannon ball   
   > will be an impressive not 1 not 2 not but 4 electrons . This is a heavy   
   > cannon ball! The gun powder will be the total energy of the   
   > annihilation 1 electron and 1 positron. We are talking E=MC^2 gun   
   > powder of 1.022 MeV or 1.602e-13 Joules in Newtonian style with a   
   > massive cannon ball of 4 electrons 2.044 MeV or 3.5632e-13 K Grams   
   > Newtonian. Let us light the fuse on this weapon of mass   
   > destruction. According to Newtonian physics the velocity will be V in   
   > meters per second = SQR( energy in joules / mass in (K gram /2 )). This   
   > makes the velocity of our cannon ball 299,780,663 meters per   
   > second. This cannon ball will go through a brick wall like it was   
   > butter.   
   >   
   > Do you see the problem? The number 229,780.663 meters per second. What   
   > on earth is the speed of light doing in Newtonian physics. They did not   
   > know the speed of light at this time. Why would our quad electron   
   > cannon ball have a velocity of exactly c calculated using only   
   > Newtonian physics V=SQR(energy / (mass/2)) ?   
      
   Hi John,   
      
   That's because YOU put it in there in the first place when you specified   
   the energy available:  "1.022 MeV or 1.602e-13 joules"  (the energy   
   coming from E = m*c^2).  Actually, that latter number for energy should   
   be 1.602*1.022 = 1.6372, which should get you even closer to c.   
      
   Gary   
      
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