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   sci.physics.research      Current physics research. (Moderated)      17,520 messages   

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   Message 15,628 of 17,520   
   Roland Franzius to All   
   Re: Newtonian physics and the speed of l   
   27 May 17 09:51:38   
   
   From: roland.franzius@uos.de   
      
   Am 26.05.2017 um 09:23 schrieb John Heath:   
   > I am going to make a cannon to test Newtonian physics. The cannon will   
   > consist of gun powder and a cannon ball. The mass of the cannon ball   
   > will be an impressive not 1 not 2 not but 4 electrons . This is a heavy   
   > cannon ball! The gun powder will be the total energy of the   
   > annihilation 1 electron and 1 positron. We are talking E=MC^2 gun   
   > powder of 1.022 MeV or 1.602e-13 Joules in Newtonian style with a   
   > massive cannon ball of 4 electrons 2.044 MeV or 3.5632e-13 K Grams   
   > Newtonian. Let us light the fuse on this weapon of mass   
   > destruction. According to Newtonian physics the velocity will be V in   
   > meters per second = SQR( energy in joules / mass in (K gram /2 )). This   
   > makes the velocity of our cannon ball 299,780,663 meters per   
   > second. This cannon ball will go through a brick wall like it was   
   > butter.   
   >   
   > Do you see the problem? The number 229,780.663 meters per second. What   
   > on earth is the speed of light doing in Newtonian physics. They did not   
   > know the speed of light at this time. Why would our quad electron   
   > cannon ball have a velocity of exactly c calculated using only   
   > Newtonian physics V=SQR(energy / (mass/2)) ?   
   >   
   >   
      
   Thats life, you get back you insert!   
      
   Your kinetic energy is 2 m c^2, your mass is 4 m so by Newton you have   
   1/2 *4m *c^2 = 2 m c^2.   
      
   This is completly independent of the numerical value of c. We only have   
   to assume the approximate Newtonian formula   
      
   E = mc^2 + 1/2 m v^2 -.+.-   
      
   In fact the total energy including rest energy mc^2 is   
      
   E = mc^2 /sqrt(1-v^2/c^2)   
      
   going to infinity as v->c.   
      
   The kinetic energy as the difference between total energy and rest energy   
      
   T = E - m c^2 = mc^2 /sqrt(1-v^2/c^2) -mc^2 = 4 m c^2   
      
   yields sligthly less than c   
      
   1-v^2/c^2 =1/5   
   v = c 2/sqrt(5)   
      
   --   
      
   Roland Franzius   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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