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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,520 messages    |
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|    Message 15,628 of 17,520    |
|    Roland Franzius to All    |
|    Re: Newtonian physics and the speed of l    |
|    27 May 17 09:51:38    |
      From: roland.franzius@uos.de              Am 26.05.2017 um 09:23 schrieb John Heath:       > I am going to make a cannon to test Newtonian physics. The cannon will       > consist of gun powder and a cannon ball. The mass of the cannon ball       > will be an impressive not 1 not 2 not but 4 electrons . This is a heavy       > cannon ball! The gun powder will be the total energy of the       > annihilation 1 electron and 1 positron. We are talking E=MC^2 gun       > powder of 1.022 MeV or 1.602e-13 Joules in Newtonian style with a       > massive cannon ball of 4 electrons 2.044 MeV or 3.5632e-13 K Grams       > Newtonian. Let us light the fuse on this weapon of mass       > destruction. According to Newtonian physics the velocity will be V in       > meters per second = SQR( energy in joules / mass in (K gram /2 )). This       > makes the velocity of our cannon ball 299,780,663 meters per       > second. This cannon ball will go through a brick wall like it was       > butter.       >       > Do you see the problem? The number 229,780.663 meters per second. What       > on earth is the speed of light doing in Newtonian physics. They did not       > know the speed of light at this time. Why would our quad electron       > cannon ball have a velocity of exactly c calculated using only       > Newtonian physics V=SQR(energy / (mass/2)) ?       >       >              Thats life, you get back you insert!              Your kinetic energy is 2 m c^2, your mass is 4 m so by Newton you have       1/2 *4m *c^2 = 2 m c^2.              This is completly independent of the numerical value of c. We only have       to assume the approximate Newtonian formula              E = mc^2 + 1/2 m v^2 -.+.-              In fact the total energy including rest energy mc^2 is              E = mc^2 /sqrt(1-v^2/c^2)              going to infinity as v->c.              The kinetic energy as the difference between total energy and rest energy              T = E - m c^2 = mc^2 /sqrt(1-v^2/c^2) -mc^2 = 4 m c^2              yields sligthly less than c              1-v^2/c^2 =1/5       v = c 2/sqrt(5)              --              Roland Franzius              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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