From: g.scholten@nospam.gmx.de
John Heath wrote:
> I am going to make a cannon to test Newtonian physics. The cannon will
> consist of gun powder and a cannon ball. The mass of the cannon ball
> will be an impressive not 1 not 2 not but 4 electrons . This is a
> heavy cannon ball! The gun powder will be the total energy of the
> annihilation 1 electron and 1 positron.
I highly doubt that you will be able to realize such an experiment in
practice. So, obviously, it is rather a thought experiment what you
descibe here.
> We are talking E=MC^2 gun
> powder of 1.022 MeV or 1.602e-13 Joules in Newtonian style with a
> massive cannon ball of 4 electrons 2.044 MeV or 3.5632e-13 K Grams
> Newtonian. Let us light the fuse on this weapon of mass
> destruction. According to Newtonian physics the velocity will be V in
> meters per second = SQR( energy in joules / mass in (K gram /2 )).
> This makes the velocity of our cannon ball 299,780,663 meters per
> second.
According to Newtonian Mechanics, it would. However, Newtonian Mechanics
is known to break down for velocities that are not << c.
> Do you see the problem? The number 229,780.663 meters per second. What
> on earth is the speed of light doing in Newtonian physics. They did
> not know the speed of light at this time. Why would our quad electron
> cannon ball have a velocity of exactly c calculated using only
> Newtonian physics V=SQR(energy / (mass/2)) ?
As Gary already pointed out: because you explicitly entered that speed
into the formulas. You explicitly assumed that the kinetic energy is
E_kin = 2 me c^2
with me being the known mass of the electron, me = 9.1E-31 kg, and c
being 229,780,663 m/s. So, combining this with Newtonian formula
E_kin = 1/2 m v^2
with m = 4 me being the mass or your cannon ball and c the resulting
speed of that ball, the result is v = c = 229,780,663 m/s, the number
you explicitly entered.
--- SoupGate-Win32 v1.05
* Origin: you cannot sedate... all the things you hate (1:229/2)
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