XPost: sci.astro.research   
   From: jos.bergervoet@xs4all.nl   
      
   On 5/30/2017 6:55 AM, Phillip Helbig (undress to reply) wrote:   
   > A smooth distribution corresponds to high entropy and a lumpy one to low   
   > entropy if gravity is not involved.  For example, air in a room has high   
   > entropy, but all the oxygen in one part and all the nitrogen in another   
   > part would correspond to low entropy.   
   >   
   > If gravity is involved, however, things are reversed: a lumpy   
   > distribution (e.g. everything in black holes) has a high entropy   
      
   But if everything is in one big black hole, and the black hole   
   would need only mass and angular momentum and charge to describe   
   it, then that would be extremely low entropy (and essentially we   
   would have back the "ordinary" behavior you described first).   
      
   So the difference is only in the entropy that is in the "soft   
   supertranslation hair" (if that is the correct theory..)   
      
   If the oxygen in one corner of the room would also have this   
   extra entropy that black holes seem to have (for whatever reason),   
   then the cases would be the same.   
      
   Provided of course that before black hole formation occurs   
   the normal behavior (lumpy distribution has lower entropy) is   
   respected by gravity as it is by other forces. So the question   
   is: would there still be a reason, in cases without black holes,   
   to expect that gravity is different?   
      
   --   
   Jos   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)