From: goldenfieldquaternions@gmail.com   
      
   On Monday, June 26, 2017 at 9:18:15 AM UTC-5, Tom Roberts wrote:   
   > On 6/25/17 6/25/17   2:26 AM, Lawrence Crowell wrote:   
   > > On Saturday, June 24, 2017 at 3:15:06 PM UTC-5, Gregor Scholten wrote:   
   > >> Lawrence Crowell  wrote:   
   > >>   
   > >>> The anti-screening effect of color charge does result in this   
   > >>> inverted runn= ing coupling. What this does mean is that very high   
   > >>> energy QCD is reasonabl= y tractable. This conforms to a usual   
   > >>> situation that scattering states can = be computed well enough, but   
   > >>> bound states are tough.   
   > >>>   
   > >>> As sqrt{s} --> 0 the number of diagrams blows up and they all   
   > >>> contribute eq= ually.   
   > >>   
   > >> What does s mean? Obviously, you do not denote a spatial distance with s,   
   > >> right?   
   > >   
   > > The Mandelstam variables are s, t, u. Often the transverse momentum in a   
   high energy process is referred to as sqrt{s}.   
   >   
   > OOPS! s is NOT transverse, the transverse variables are t and u (they are   
   > squares of momentum transfers). Sqrt(s) is the total energy, and is by far   
   the   
   > most commonly used of the three (e.g. the Particle Data Group plots total   
   > cross-sections against sqrt(s)). Note all three Mandelstam variables are   
   > invariant. They are defined for a 2-particle state scattering into a   
   2-particle   
   > state.   
   >   
   > Tom Roberts   
      
   You are right, my bad. I for some reason thought that with it being   
   s channel and space that it was transverse.   
      
   LC   
      
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