From: goldenfieldquaternions@gmail.com   
      
   On Monday, June 26, 2017 at 9:25:04 PM UTC-5, James Goetz wrote:   
   > A zero-energy universe has a 1:1 ratio of negative gravitational force   
   > to positive force. Gravitons with zero mass could cohere with the field   
   > equations of general relative. Gravitons would have a 2 spin and for   
   > the sake of simplicity they would constitute the negative force.   
   > Photons have a 1 spin and constitute most of the positive force.   
   > Estimates indicate that the observable universe has 10^90 photons.   
   > Assuming general relativity, quantum gravity, and a zero-energy   
   > universe, what is the ratio of gravitons to photons?   
      
   The zero universe is based on the ADM constraint NH = 0. The vanishing   
   of the Hamiltonian in the Friedman LeMaitre Robertson Walker (FLEW)   
   spacetime is   
      
   H = 0 = 1/2(a'/a) - 4piGp/3 + k/a^2,   
      
   where a is the expansion scale parameter, a' = da/dt and p is the   
   density of mass-energy. k = 1 or -1 for spherical or hyperbolic   
   spacetime and k = 0 for flat spacetime. The density of mass energy   
   has various terms for matter, radiation and constant for vacuum.   
      
   LC   
      
   --- SoupGate-Win32 v1.05   
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