From: fortunati.luigi@gmail.com   
      
   I'm standing in front of the mirror at a distance  with my clock that   
   marks the time .   
      
   The clock image in the mirror marks a delayed time of 2d/c (compared to   
   t) due to the time it takes to light to get to the mirror and return (as   
   long as i stand still and the mirror as well).   
      
   But what if I am running at constant speed parallel to the mirror? The   
   distance is always equal to  but the light does not go and goes back   
   to the same point, because in the meantime I have moved away.   
      
   And then the light has to travel a greater distance due to the   
   inclination of the path and therefore the delay time of the clock image   
   is greater than 2d/c.   
      
   This longer delay measures my speed compared to the mirror.   
      
   What if the mirror was moving while I was still standing?   
      
   In that case, the light should no longer extend its path because it   
   would leave me firm and return from me always.   
      
   If all this was true (and it is not possible) it would be enough to   
   compare the time of the watch with that of the image to find out if one   
   moves or moves the other: if the delay is equal to 2d/c it moves the   
   mirror, if it is the bigger the clock moves.   
      
   How is it possible?   
      
   --   
   Luigi Fortunati   
      
   Credere e' piu' facile che pensare   
   Believing is easier than thinking   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)