From: sylvia@not.at.this.address   
      
   On 29/08/2017 5:21 PM, Luigi Fortunati wrote:   
   > I'm standing in front of the mirror at a distance  with my clock that   
   > marks the time .   
   >   
   > The clock image in the mirror marks a delayed time of 2d/c (compared to   
   > t) due to the time it takes to light to get to the mirror and return (as   
   > long as i stand still and the mirror as well).   
   >   
   > But what if I am running at constant speed parallel to the mirror? The   
   > distance is always equal to  but the light does not go and goes back   
   > to the same point, because in the meantime I have moved away.   
      
   In your frame, the distance moved by the light is unchanged.   
      
   Sylvia.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)