From: fortunati.luigi@gmail.com
Gregor Scholten sabato 02/09/2017 alle ore 12:54:33 ha scritto:
>> I'm standing in front of the mirror at a distance with my clock
>> that marks the time .
>>
>> The clock image in the mirror marks a delayed time of 2d/c (compared
>> to t) due to the time it takes to light to get to the mirror and
>> return (as long as i stand still and the mirror as well).
>>
>> But what if I am running at constant speed parallel to the mirror? The
>> distance is always equal to but the light does not go and goes
>> back to the same point, because in the meantime I have moved away.
>>
>> And then the light has to travel a greater distance due to the
>> inclination of the path and therefore the delay time of the clock
>> image is greater than 2d/c.
>>
>> This longer delay measures my speed compared to the mirror.
>>
>> What if the mirror was moving while I was still standing?
>>
>> In that case, the light should no longer extend its path because it
>> would leave me firm and return from me always.
>
> In both cases (you are moving and the mirror is moving), you can
> consider things either in your own rest frame or in the mirror's rest
> frame.
>
> In your own rest frame S, the path of the light has the length s = 2d,
> and therefore, the light takes the time interval
>
> Delta_t = s/c = 2d/c
>
> for the path.
>
> In the mirror's rest frame S', the path of the light has the longer
> length s' > 2d/c, and therefore takes the longer time interval
>
> Delta_t' = s'/c > 2d/c
>
> This difference in the time interval is what is known as relativistic
> time dilation.
>
> This is true for both cases, so both cases are fully equivalent. It's
> just a matter of the frame of reference you chose (your own or the
> mirror's).
>
>
>> If all this was true (and it is not possible) it would be enough to
>> compare the time of the watch with that of the image to find out if
>> one moves or moves the other: if the delay is equal to 2d/c it moves
>> the mirror, if it is the bigger the clock moves.
>
> In your own rest frame, the time delay is always Delta_t = 2d/c.
I thank you and others who have responded.
But if the image had an internal clock, what time would it be?
First it would see moving the P point of the train at speed c to the
distance and then it would always approach it at speed c for a
similar distance d, so its clock would mark the time interval
delta=2d/c, in accordance with what you wrote.
But if he looked from the mirror side, he would first see Q (mirror)
approach from a distance greater than and then he would see him
move away for a distance greater than , and always at speed
because that is absolute and can not be different.
In this case the time interval is: delta_t > 2d/c.
What time would this clock mark? Is equal to or greater than 2d/c?
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Luigi Fortunati
--- SoupGate-Win32 v1.05
* Origin: you cannot sedate... all the things you hate (1:229/2)
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