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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 15,839 of 17,516    |
|    rockbrentwood@gmail.com to Luigi Fortunati    |
|    Re: Newton vs. Einstein -- both at the s    |
|    22 Sep 17 06:43:20    |
      On Thursday, September 21, 2017 at 1:30:37 AM UTC-5, Luigi Fortunati wrote:       > Newton claims that gravity is a force, Einstein denies it: for him it       > is not a force (it is something else).              Let's throw a wrench into the gears here!              The metric (and 0 constraint)              dx^2 + dy^2 + dz^2 - 2aU/(1 + 2aU) (x dx + y dy + z dz)^2/(x^2 + y^2 + z^2)        + 2 dt du + a du^2 - 2U dt^2 = 0       with the proper time ds given by       ds = dt + a du              gives you the Schwarzschild solution to Einstein's equations when a > 0 (with       light speed c = root(1/a)) and Newton's law of gravity when a = 0! I       n that case, the metric (and 0 constraint) becomes       dx^2 + dy^2 + dz^2 + 2 dt du - 2U dt^2 = 0,       with proper time ds = dt.              Apply the geodesic equation (and use the above 0-constraint) to a test body       and you will, indeed, find that the body conforms to what's expected for       a > 0 AND a = 0. The coordinate u -- in all cases -- will yield the negative       of the action per unit mass.              To obtain the mass shell condition, invert the metric and apply the       correspondence:       del <-> p, -(d/dt)_u = H = kinetic energy, (d/du)_t = m       and note that corresponding to the invariant ds is the invariant m.              In flat space (where U = 0), this produces the result        p^2 - 2mH - a H^2 = 0       which for a > 0 is just the familiar mass shell constraint, provided you take       E = H + m/a. For a = 0 it is also the mass shell constraint, only here       the mass-energy-momentum vector is a 5 vector (p_x, p_y, p_z, H, m) (and       transforms as such). The transform for a > 0 is similar, except it can be       factored out by replacing H with E.              > It is obvious that both can not be right: if gravity is a force, Newton       > is right and Einstein is wrong, and if it is the reverse Newton is       > wrong and Einstein is right.              I think we've just blown the entire question out of the water (and, you're       welcome). Even Cartan would envy this direct simplicity. :)              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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