From: jos.bergervoet@xs4all.nl   
      
   On 9/29/2017 3:20 PM, John Heath wrote:   
   > A car is moving at .1 c. The tire on the road at 6:00 o'clock , bottom ,   
   > is moving at 0 c as it is touching the road but at 12:00 o'clock , top ,   
   > the tire is moving at .2 c twice as fast as the car.   
      
   No, the correct combining of the two speeds will give   
     0.19802 * c   
   Look up:   
      
      
   > Does this mean the   
   > car is limited to speed .5 c   
      
   No, because the correct formula (in the link above)   
   will allow higher speeds, up to c.   
      
   >     as at this speed the top of the tire will   
   > be moving at c twice as fast as the car ?   
      
   No, not twice as fast. Only twice as fast divided by   
   1+(v/c)^2 (But do check the correct tyre pressure!)   
      
   --   
   Jos   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)