home bbs files messages ]

Forums before death by AOL, social media and spammers... "We can't have nice things"

   sci.physics.research      Current physics research. (Moderated)      17,516 messages   

[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]

   Message 15,934 of 17,516   
   John Heath to Tom Roberts   
   Re: The "apparent" forces   
   20 Nov 17 13:36:06   
   
   From: heathjohn2@gmail.com   
      
   On Sunday, November 19, 2017 at 5:01:39 AM UTC-5, Tom Roberts wrote:   
   > On 11/16/17 11/16/17   3:20 AM, John Heath wrote:   
   > > There is another issue with centrifugal force that as not been   
   > > addressed.   
   >   
   > It has not been addressed because it is not an issue. It is, rather, a   
   > confusion on your part.   
   >   
   > > The force is outward from the center however when the string   
   > > is cut the direction is at 90degrees to the direction of the force wher=   
   e   
   > > the ball spinning when released will move in a straight line forward no=   
   t   
   > > outward. The force felt was outward but when free the direction taken   
   > > was at 90 degrees to the force ?   
   >   
   > You are confusing velocity with force.   
   >   
   > Before the string is cut, the force on the ball is radially inward, and   
   > its velocity is tangential to the circle around which it travels. For   
   > definiteness, let us cut the string when it lies along the positive x   
   > axis, with the ball circling CCW from above in the x-y plane. So   
   > immediately before the string is cut, the force on the ball is in the -x   
   > direction (i.e. toward the center at the origin), and the ball's   
   > velocity is in the +y direction (i.e. tangential to the circle).   
   > Immediately after being cut, there is no force on the ball, and its   
   > velocity remains in the +y direction, and off it flies in the +y   
   > direction.   
   >   
   > So there is no "issue". Yes, after the string is cut the ball moves off   
   > in a straight line tangential to the circle it followed before the cut.   
   > Yes, that circle is perpendicular to the radially-inward force on the   
   > ball (before cut).   
   >   
   > Tom Roberts   
      
   I have heard this before and it was part of the motive to make the   
   post. There is a procedure to measure the amount and direction of   
   a force with a strain gauge. I can measure the amount and direction   
   of the force of gravity , not really a force understood , and it   
   says the gravity force is 150 pounds on myself in the downward   
   direction. If I use the same procedure to measure the direction of   
   the force of a string spinning a ball the force is outwards according   
   to the same strain gauge procedure. The same could be said of an   
   orbiting satellite that is continuously falling as it goes around   
   the earth. The gravity force is inwards so the centrifugal force   
   would have to be outward for the orbit to be stable. Note there are   
   no strings in this example. The -x leading to a conclusion of a   
   inward force was caused by the mechanical limitation of the string   
   not the centrifugal force.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]


(c) 1994,  bbs@darkrealms.ca