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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 16,199 of 17,516    |
|    Gregor Scholten to Sabbir Rahman    |
|    Re: A question about spherical gravitati    |
|    21 Jun 18 07:11:41    |
      From: g.scholten@gmx.de              Sabbir Rahman wrote:              > I am not sure what you mean here. I started with the phrase "let us consider       > a ... configuration in which a black hole has just formed..." - and you are       > now stating that it has *not* just formed? Huh?       >       > Just to clarify, the black hole has formed form the perspective of the       > exterior r > 2GM, so that any matter falling inwards past r=2GM will       > inevitably hit the singularity. That is the situation I am asking you to       > consider. The interior matter at r<2GM remains oblivous to the formation of       > the black hole at this point              In fact, the latter is not true, though. As I realized in the meantime,       your main argument that the outermost shell would experience the gravity       of the mass M - dm only, instead of the full mass M, is wrong. The       reason is that every shell is self-attractive. Imagine a shell of       thickness dr as composed of elements of volume              d^3r = (g_rr)^(1/2) r sin(theta) dr dtheta dphi              each. Then these elements attract each other, making the shell as a       whole attract itself. A shell of mass dm on its own would therefore       experience the gravitational attraction of the mass dm, and as the       outermost shell of a spherically symmetric matter configuration of mass       M, it experiences the gravitational attraction of the full mass M, not       of the mass M - dm of the more inner shells only.              A shell at a radial coordinate r does not experience any gravitational       forces from more outer shells, that is correct, but experiences       gravitational forces from itself.              So, no matter if the radial coordinate R of the outermost shell is at       2GM or at 2GM - dr, in both cases the outermost shell is not able to       resist against gravity, since it experiences the gravity of the full       mass M, and therefore is unavoidably forced to fall inwards. In the same       manner as an infalling particle that crosses the radial coordinate R.              So both, the outermost shell and the infalling particle experience the       same metric.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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