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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,520 messages    |
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|    Message 16,202 of 17,520    |
|    Gregor Scholten to Luigi Fortunati    |
|    Re: The tower of the twins    |
|    23 Jun 18 18:08:40    |
      From: g.scholten@gmx.de              Luigi Fortunati wrote:              > Twin A is at the base of the tower where the watch of twin B goes       > slower than that at the top.              You mean twin A is at the bottom of the tower and twin B is at the top       of the tower?                     > Is the distance AB in the reference of the twin A greater, less or       > equal to the same distance measured in the reference of the twin B?              Obviously, you are referring to General Relativity (GR) and       gravitational time dilation. Right? However, this implies that the       concept of frames of reference is defined on short scales only, for       which the curvature of spacetime can be neglected. Near the location on       twin A, you can define a frame of reference for twin A, and near the       location of twin A, you can define a frame of reference for twin B, but       there is no frame of reference that covers a spacetime region that       contains both twins, A and B.              To describe such a spactime region, you can construct a coordinate       system, e.g. one in which both twins have fixed spatial positions. In       that coordinate system, there is a unique spatial distance AB between       both twins.              And before you ask: the light speed in that coordinate system is not       constant (unlike in the local frames of twin A and B that are defined on       local scales around twin A and B), but is lower at the bottom of the tower.                     > Second question: if there is a light signal that goes from A to B and       > back reflecting on 2 mirrors placed in A and B, the round-trip time       > (from A to B and from B to A) measured by the clock of the twin A is       > greater, less or equal to the time measured by B for the path from B to       > A and from A to B?              With twin A at the bottom and twin B at the top of the tower, the round       trip time for the trip A -> B -> A measured by the clock of twin A is       less than the round trip time for the trip B -> A -> A measured by the       clock of twin B.              Assume you the coordinate system you constructed shows time translation       invariance, like Schwarzschild coordinates do. Then the half trip A -> B       always takes the same coordinate time Delta_t_AB, and the half trip B ->       A always takes the same coordinate time Delta_t_BA. So, the round trip       coordinate time for both trips A -> B -> A and B -> A -> B is the same:              Delta_t_ABA = Delta_t_BAB = Delta_t_AB + Delta_t_BA              Considered in Schwarzschild coordinates, the clock of twin A runs slower       than the clock of twin B, compared to coordinate time. So, the round       trip coordinate time Delta_t_ABA corresponds to a proper time interval       Delta_tau_A in the proper time of twin A that is shorter than the       corresponding proper time interval Delta_tau_B in the proper time of twin B.              That's why twin A sees signals from twin B blue-shifted and twin B sees       signals from twin A red-shifted.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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