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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 16,304 of 17,516    |
|    Gregor Scholten to jmreno    |
|    Re: Expanding universe    |
|    28 Jul 18 13:42:19    |
      From: g.scholten@gmx.de              jmreno wrote:              >> Can the fact that galaxies are receding from each other faster       >> than light violate causality?       >>       >       > The universe is expanding because space itself is expanding.       >       > And since space and time are intrinsically linked, maybe it is spacetime       > that is expanding.       >       > That would mean that time is expanding along with space.       >       > Presumably, that means that time is slowing down.              If we follow General Relativity (GR), there is no such thing like       expansion of spacetime or expansion of time. There is time dilation, but       that is something different. Let's consider more in detail what gives       movitation for the statement "space is expanding":              In cosmological solutions of GR, one usually assumes that on large       scales, the curvature of spacetime is described by the       Friedmann-Lemaitre-Roberson-Walker (FLRW) metric. This can be expressed as              ds^2 = -(c dt)^2 + S(t)^2 [dr^2 / (1 - k r^2) +        r^2 (dtheta + sin(theta)^2 dphi^2]              where (t,r,theta,phi) are so-called co-moving coordinates. S(t) is the       scale factor, k is the so-called curvvature index (for curvature of       space, not of spacetime), that can be -1, 0 or +1. Now consider two       galaxies, one located at r = 0, the other at r = r0. The spatial       distance between both galaxies, i.e. the distance on a spacelike       hypersurface defined by t = const (<=> dt = 0), is given by              D = \int_0^r0 [S(t) / (1 - k r^2)^(1/2)] dr              what equals D = S(t) r0 for k = 0. Now, if the universe is expanding,       the scale factor S(t) is increasing by time: dS/dt > 0, so that the       spatial distance between both galaxies increases by time, too. In other       words: the two galaxies move apart.              However, this movement does not yield special-relativistic effects like       time-dilation. For the proper time dtau = 1/c (-ds^2)^(1/2) that elapses       for each galaxy, we find, with ds = dtheta = dphi = 0 since each galaxy       has a fixed spatial position in the co-moving coordinates:              dtau = 1/c (-ds^2)^(1/2) = dt              So, the proper time tau matches the coordinate time t.              For comparison: in Special Relativity (SR), if we consider a body moving       with velocity v = dx/dt in x-direction with respect tome some inertial       frame (t,x,y,z) in which the (Minkowskian) metric is              ds^2 = -(cdt)^2 + dx^2 + dy^2 + dz^2              we get              dtau = 1/c [(c dt)^2 - dx^2]^(1/2)        = (dt^2 - dx^2/c^2)^(1/2)        = (dt^2 - v^2 dt^2 /c^2)^(1/2)        = (1 - v^2/c^2)^(1/2) dt              what is the well-known formula for time-dilation.              That's why we say that in SR, bodies are moving on their own, yielding       time dilation, whereas when galaxies move apart due to the expansion of       the universe, there is no time dilation because the galaxies do not move       on their own, but space is expanding between them.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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