From: fortunati.luigi@gmail.com   
      
   The second principle says that F=m*a and F1=m1*a1. (1)   
      
   The third principle says that for every action F corresponds an equal   
   and opposite F1 reaction, ie an F1 such that F1=-F. (2)   
      
   Substituting the (2) to (1) we have F=m*a and -F=m1*a1.   
      
   Adding the first and second members we have: F-F=(m*a)+(m1*a1), from   
   which the corollary: m*a=-(m1*a1) in which there are no forces but only   
   equivalences between different masses with different accelerations.   
      
   Can we therefore say that for every quantity of "accelerating mass"   
   (m*a) there is always another equal quantity of "accelerating mass"   
   (m1*a1) in the opposite direction?   
      
   [[Mod. note -- No.   
   -- jt]]   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)