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| sci.physics.research | Current physics research. (Moderated) | 17,516 messages |
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| Message 16,466 of 17,516 |
| Stefan Ram to Stefan Ram |
| Re: Energy Conservation Question (1/4) |
| 12 Apr 19 10:59:34 |
From: ram@zedat.fu-berlin.de
ram@zedat.fu-berlin.de (Stefan Ram) writes:
>Since this linear tangential speed (the linear tangential
>momentum of the lowered mass) is a conserved quantity, it
>must be reduced somehow (via the cable?). (The Earth's
Here are the results of some simulations I ran using gcc.
First, a geostationary satellite S with a mass of 1,000 kg
orbiting the earth E. "S" is the position of the satellite
at the end of the simulation, where it is near its start
position again.
#######################################################################
# #
# ss #
# sssS sssssss #
# sss sss #
# sss sss #
# ss ss #
# ss ss #
# s s #
# ss E ss #
# ss ss #
# s s #
# ss ss #
# ss ss #
# sss sss #
# sss sss #
# ssssssssssssssss #
# #
# #
#######################################################################
Now, the satellite is given a push towards the earth at the
start of the simulation when it is at the top in the image
(it then starts to moves to the right and down) Effectively,
this moves its orbit to the left, but the satellite is not
falling onto our Earth.
FLOAT dsy{ -1000 }; /* satellite's vertical velocity comp. */
#######################################################################
# #
# sssssS s #
# sssss sssss #
# sss sss #
# sss sss #
# ss ss #
# ss ss #
# s s #
# s E s #
# s s #
# s ss #
# ss s #
# ss ss #
# sss sss #
# sss sss #
# sssss ssssss #
# sssssssssss #
# #
#######################################################################
Next, the satellite is placed at the same spot as before (at
the top in the image), but with only half the velocity
needed for the circular geostationary orbit it had on the
first image. It starts to fall towards the Earth, but then
enters an elliptic orbit instead of landing on the earth.
(Atmosphere is not simulated.)
FLOAT dsy{ dgy/2 }; /* satellite's vertical velocity comp. */
FLOAT dsx{ dgx/2 }; /* satellite's horizontal velocity comp. */
#######################################################################
# #
# s #
# ssss #
# sS ss #
# ss ss #
# s s #
# s s #
# ss ss #
# ss E ss #
# ssssssss #
# ss #
# #
# #
# #
# #
# #
# #
# #
#######################################################################
Finally, the speed of the satellite is multiplied with 0.99999
every second. This seems to be the way to go when one wants to
land at the Earth. One needs retrorockets or something equivalent
to get rid of the kinetic energy. We /need/ more energy just to
/reduce/ our kinetic energy! The satellite is spiraling down
towards the Earth.
dsx *= static_cast< FLOAT >( 0.99999 );
dsy *= static_cast< FLOAT >( 0.99999 );
#######################################################################
# #
# ss #
# sssssss #
# sss #
# ss #
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