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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 16,467 of 17,516    |
|    stargene to stargene    |
|    Re: Lambda^-1 as cosmic computational po    |
|    12 Apr 19 12:11:49    |
      From: stargene@sbcglobal.net              [[Mod. note -- As received in the s.p.r moderation system, this       posting contained many non-ASCII characters. I have corrected a few       of them whose meaning was clear, but many more remain. AUTHORS, PLEASE       POST ONLY 7-BIT-CLEAN ASCII SO YOUR POSTING ISN'T MANGLED BEFORE THE       MODERATORS AND NEWSGROUP READERS GET TO SEE IT!!!       -- jt]]              On Sunday, April 7, 2019 at 12:14:46 PM UTC-7, stargene wrote:              > 2. I think the answer to the author's first question is,       > "These quantities have different units -- one is an energy       > density, whereas the other is a dimensionless number       > (the inverse of "number of operations"). So any coincidence       > between their numerical values is almost certainly just       > that, a coincidence.       > -- jt]]       >       Yes, lambda is often expressed as energy density (but acting as       a negative pressure). Whether expressed as energy density, or,       as in the Einstein field equations, as (1/distance)squared , or       other parameters seems a matter of context. As the entry       on the cosmological constant in the wiki entry states, "..Given the       Planck (2018) values of =CE=A9_=CE=9B = 0.6889=C2=B10.0056 and H_0       = 67.66=C2=B10.42 (km/s)/Mpc = (2.1927664=C2=B10.0136)=C3=9710--18 s^-1,       =CE=9B has the value =1.1056 x10^-52 m^-2       or 2.888=C3=9710^-122 in reduced Planck units.."              We get the quoted wiki Planck units value, by using the scaling       factor for (meter/Planck length)^2 ie: 1m / (1.616*10^-35m)^2,       which is 3.8 * 10^69. Dividing 1.1056 *10^-52 m^2 by 3.8 *10^69       gives the stated reduced Planck unit value 2.88 *10^-122 (in       units of Planck areas, A_pl). This unit of expression is generally       implied when considering the entropy of a black hole, where the       entropy S ~ A_bh / A_pl (A_bh is area of black hole.) It is in this       context that black holes have been conjectured to be the ultimate       quantum computers.              Thus, S for a stellar mass BH might be say ~10^77. While this is       a dimensionless number, it is clear that S also stands for the area       of the event horizon in Planck area units.              My point is that expression in Planck units (mass, length, area,       time) being fundamental, may act as if effectively dimensionless       in some contexts. In that sense, my extension of Lloyd's result       and the lambda estimation may not be quite so immiscible. Ie:       the age of our universe can be stated in Planck units, where       t_pl= 10^-44 sec, the age of our universe is 10^61 units in Planck       time. So we might say that in this sense, a total universe       computational power, a la Lloyd, might be "an average of ~10^60       quantum operations per every Planck time unit", over the       holographic boundary of, and across the age, of the universe.              It's also worth noting that the most recent Planck based value       for lambda , quoted above as "2.888*10^-122 in reduced Planck       units" [ie: where Planck area ~ 10^-70 m^2] can be inverted       to read 3.46*10^121 * Planck area. This roughly equals the       boundary surface area of the universe ~ 9.05*10^51 m^2. That       is, 1 / lambda can be roughly construed as the entropy of our       universe.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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