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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 16,471 of 17,516    |
|    Rich L. to J.B. Wood    |
|    Re: The "Force" of Gravity    |
|    18 Apr 19 10:48:52    |
      From: ralivingston1952@charter.net              On Wednesday, April 17, 2019 at 6:28:35 PM UTC-5, J.B. Wood wrote:       > Hello, all. One concept that I can seem to get my thoughts around is       > that arguably gravitational force fits in to the Newtonian concept of a       > force that can act on a mass. But general relativity informs us that       > gravity isn't a force at all but a phenomenon due to the curvature of       > space-time. How can merely the curvature of space give rise to the fact       > that two untethered masses will tend to be attracted to and move toward       > one another? We've seen those rubber-sheet demos but they rely on       > earth's gravity and we end up with a cause-effect-cause situation?       > Thanks for your time and comment. Sincerely       > --       > J. B. Wood e-mail: arl_123234@hotmail.com              The key to understanding how general relativity explains gravity       is to focus on the time metric component, g_00. This is the component       that results in the gravitational red shift, which, in simple terms,       says that an oscillator at one elevation in a gravitational field       will appear to have a lower frequency when viewed from a higher       elevation, and conversely will appear to have a higher frequency       when viewed from a lower elevation. (it is incorrect to say that       the frequency changes; no matter where the oscillator is located,       an observer at the same elevation will always observe the same       frequency.)              Now consider a particle at rest (momentarily) in a gravitational       field. As reqpresented in quantum mechanics this particle will be       a wave function with a frequency proportional to its mass, and the       wave function will be a fuzzy blob extending over some region of       space. Because the particle is at rest, all parts of the wave       function will have the same phase. Because of the gravitational       red shift, the lower parts of this wave function will change phase       at a lower frequency than higher parts. As a result the wave       function will quickly get out of phase. The result is a linear       change in phase with altitude, which quantum mechanically means it       has momentum, and it is a momentum that grows with time. i.e. a       force.              Rich L.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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