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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 16,650 of 17,516    |
|    PengKuan Em to All    |
|    Re: Testing relativity of simultaneity u    |
|    06 Nov 19 08:08:26    |
      From: titang78@gmail.com              Le jeudi 31 octobre 2019 21:56:14 UTC+1, richali...@gmail.com a écrit :       >       > Special Relativity only applies to inertial frames in flat space-time.       > Satelites in orbit are not in flat space-time, even though they are in       > locally inertial frames. To properly analyze this case you need GR,       > which I assume would handle it correctly.       >       > Rich L.              The local frame at any point in general relativity is a locally inertial       frame. In such frame, relativity of simultaneity applies, so the time of       point 1 and 2 are different. Suppose they are t'1 and t'2 and       dt'=t'2-t'1 in frame 1. then, in frame 2 next to frame 1, we have       dt'=t'3-t'2. So, we have       t'2=dt'+t'1 in frame 1. Suppose t'1=0. Then,t'2=dt'. Then, we have       successively,       t'3=dt'+t'2=2*dt' in frame 2       t'4=dt'+t'3=3*dt' in frame 3       ...       t'(n+1)=dt'+t'n=n*dt' in frame n              So, the time of the satellite n+1 is n*dt' even in GR. But satellite n+1       is satellite 1 and its time should be 0. Hence, even in GR, relativity       of simultaneity leads to contradiction.              PK              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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