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|    Message 16,652 of 17,516    |
|    richalivingston@gmail.com to PengKuan Em    |
|    Re: Testing relativity of simultaneity u    |
|    06 Nov 19 21:13:18    |
      On Wednesday, November 6, 2019 at 2:08:29 AM UTC-6, PengKuan Em wrote:       > Le jeudi 31 octobre 2019 21:56:14 UTC+1, richali...@gmail.com a écrit :       > >       > > Special Relativity only applies to inertial frames in flat space-time.       > > Satelites in orbit are not in flat space-time, even though they are in       > > locally inertial frames. To properly analyze this case you need GR,       > > which I assume would handle it correctly.       > >       > > Rich L.       >       > The local frame at any point in general relativity is a locally inertial       > frame. In such frame, relativity of simultaneity applies, so the time of       > point 1 and 2 are different. Suppose they are t'1 and t'2 and       > dt'=t'2-t'1 in frame 1. then, in frame 2 next to frame 1, we have       > dt'=t'3-t'2. So, we have       > t'2=dt'+t'1 in frame 1. Suppose t'1=0. Then,t'2=dt'. Then, we have       > successively,       > t'3=dt'+t'2=2*dt' in frame 2       > t'4=dt'+t'3=3*dt' in frame 3       > ...       > t'(n+1)=dt'+t'n=n*dt' in frame n       >       > So, the time of the satellite n+1 is n*dt' even in GR. But satellite n+1       > is satellite 1 and its time should be 0. Hence, even in GR, relativity       > of simultaneity leads to contradiction.       >       > PK              The satellites are not in an inertial frame as required by SR, at any       instant they can be considered in an inertial frame at some velocity,       but a moment later they are in a different frame. In SR boosts to       different frames is not a linear process. You can't just add the time       differences as you are suggesting. Look up Thomas Precession.              Consider viewing the satellites from the north pole, with all the       satellites in an equatorial orbit. If all the satellites are at the       same altitude the (GR) gravitational red shift will be equal for all of       them. They are all moving at the same speed in this orbit, so the SR       time dilation will also be the same. You could synchronize the clocks       with a single pulse from the north pole. The orbiting clocks are now       synchronized and running at the same speed. Doesn't that counter your       argument?              Rich L.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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