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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 17,121 of 17,516    |
|    Rock Brentwood to Luigi Fortunati    |
|    Re: The Direction of geodesics    |
|    07 Oct 22 09:16:55    |
      From: rockbrentwood@gmail.com              On Wednesday, September 7, 2022 at 1:22:46 AM UTC-5, Luigi Fortunati wrote:       > A geodesic passes from A and also from B.       >       > Is the direction from A to B fully equivalent to the direction from B       > to A?       >       > Or can it happen that one of the two directions prevails over the       > other?              In any metric geometry, around each point is a neighborhood U,       such that between any two points A and B in U       lies a unique geodesic between A and B.       Uniqueness means it's therefore the same regardless of direction.              This even includes non-Riemannian geometries,       like the chronogeometry of Newtonian gravity,       which can be regarded as residing on a light cone       of the 4+1 dimensional pseudo-Riemannian chronogeometry       given by the metric whose line element is              dx^2 + dy^2 + dz^2 + 2 dt du - 2V dt^2              where V = -GM/r (with r^2 = x^2 + y^2 + z^2)       is the gravitational potential per unit mass.              This also works perfectly well for multi-body potentials,       V = -sum_a (-GM_a/|r - r_a|).              Its geodesics comprise the orbital motions of Newtonian gravity       AND the geometrical instantaneous geodesics of space at any instant.              You may be hard-pressed, in this case, to account for       what the corresponding geodesic *distances* are,       since everything is zero on a light cone!       All the geodesics for Newtonian gravity       are null curves in 4+1 dimensions.       But it's the same in both directions.              This may be compared to the Schwarzschild metric       which is equivalently given as light cones       in the 4+1 dimensional chronogeometry       whose metric has the following line element              dx^2 + dy^2 + dz^2 + 2 dt du - 2V dt^2       + alpha du^2 - 2 alpha V dr^2/(1 + 2 alpha V)              where dr^2 = (x dx + y dy + z dz)^2/r^2 and alpha = (1/c)^2.              This is a deformation of the Newtonian chronogeometry,       from alpha = 0 to alpha > 0.       Here, however, V = -GM/r is only for one body, not many.       There may exist similar deformations for the many-body cases.              The geodesic distances on the light cones       in the (4+1)-dimensional chronogeometry are all 0,       since all the curves on the light cones are null.       The light cones, however (unlike the Newtonian case)       comprise metric geometries in their own right -       that is: the Schwarzschild chronogeometries,       whose the metric yields - for time-like curves -       a proper time equal to s = t + alpha u.       It's the same in both directions.              In the alpha = 0 case, which is Newtonian gravity,       the (3+1)-dimensional chronogeometry continues to have       s = t + alpha u as an invariant ... which is now just s = t.       So, it can still be taken as a metric of sorts for time-like curves.       Ordinary time is proper time for Newtonian gravity.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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