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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 17,237 of 17,516    |
|    Richard Livingston to Luigi Fortunati    |
|    Re: The internal force    |
|    04 Apr 23 11:39:23    |
      From: richalivingston@gmail.com              On Monday, April 3, 2023 at 2:26:36=E2=80=AFPM UTC-5, Luigi Fortunati wrote:       > Richard Livingston il 02/04/2023 05:55:09 ha scritto:       > >> Luigi Fortunati il 30/03/2023 15:59:01 ha scritto:       ...       > >       > > A more precise way to model this, the way it is done in computer codes       > > of elastic collisions, is to model the material as a fine array of mass       ...       > >       > > Rich L.       > I agree with you: the impulse of the collision goes leftward from       > particle E to A but not with the same intensity.       >       > Is it correct to say that the exchange of forces decreases in the       > proportion of 5 between F and E, 4 between E and D, 3 between D and C,       > 2 between C and B and 1 between B and A?       >       > Luigi Fortunati       >       > [[Mod. note --       > ...       > 2. I don't quite know what you mean by the term "exchange of forces".       > But if we interpret your question as asking if the forces       > F_FE = the force F exerts on E       > F_ED = the force E exerts on D       > F_DC = the force D exerts on C       > F_CB = the force C exerts on B       > F_BA = the force B exerts on A       > are in the ratio 5:4:3:2:1, then we can apply Newton's 2nd law to try       > to find out. To do this, let's introduce a bit of terminology: Let's       > ...       > ratio 5:4:3:2:1. Figuring out the actual (time-dependent) forces       > requires a more careful analysis of the dynamics of the collision.       > -- jt]]              As Luigi has modeled it, the ball is a one dimensional transmission       line. Object F applies an impulse on E causing the "spring" between       them to compress and bringing E to a stop. Then E applies an       impulse on D compressing that spring and bringing D to a stop.       etc. etc. When the impulse reaches A there is nothing beyond       A to apply an impulse to. As a result A not only stops but reverses       direction. This stretches the "spring" between A and B causing B       to reverse direction, pulling on C, etc. The final result is that the       ball bounces off the wall and flies off to the left.              In answer to Luigi's question, all the impulses are the same       magnitude, just applied at different times per the speed of       sound.              Read up on transmission lines for a more detailed understanding.              Rich L.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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