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|    sci.physics.research    |    Current physics research. (Moderated)    |    17,516 messages    |
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|    Message 17,308 of 17,516    |
|    Tom Roberts to Luigi Fortunati    |
|    Re: Twin watches    |
|    26 Sep 23 07:36:47    |
      From: tjoberts137@sbcglobal.net              On 9/17/23 1:24 AM, Luigi Fortunati wrote:       > If clocks A and B are stopped, they remain synchronized.              No. A stopped "clock" is not a clock, so "synchronized" is meaningless.       Fortunately you did not attempt to use this silliness.              You omitted important information about the physical situation. I       presume you mean clock B is located on the ground next to a rotating       carousel, and clock A is fixed to the carousel on its rim, so the two       clocks repeatedly meet, once per rotation of the carousel. For       simplicity, I also presume the ground is an inertial frame. (Your       animation confirms most of this.)              > If clock B stands still and clock A moves (land reference), every       > time they meet clock A lags behind.              Yes, between meetings clock A experiences less elapsed proper time       than does clock B. This is just a demonstration of the twin paradox.              > If clock A stands still and clock B moves (reference of the       > carousel), every time they meet clock B lags behind.              No! The elapsed proper time between meetings for each clock is an       invariant. So it does not matter which coordinates one uses as a       reference, clock A always has less elapsed proper time between meetings       than does clock B.              You seem to have fallen into the trap of believing that "moving clocks       run slow". That oft-repeated sound bite is FALSE in several different ways:        1. The moving clock ITSELF does not "run slow", because all        clocks ALWAYS tick at their usual rate [#]. It's just that        it is OBSERVED to run slow by an inertial frame relative to        which it is moving.        2. This only applies to a moving clock being observed by an        inertial frame. For a non-inertial observer, that sound        bite may or may not apply (it takes a real calculation).               [#] If this were not true, Einstein's first postulate        of SR could not be valid.              Your animation is woefully incorrect.              [[to the moderator]]       This is not the Sagnac effect, this is merely the fact that different       paths between a given pair of endpoints can have different path lengths       (aka elapsed proper time for timelike paths).              Tom Roberts              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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