From: dr.j.thornburg@gmail-pink.com   
      
   In article , I wrote   
   > In the vertical-ice system, consider an imaginary horizontal line $hx$   
   > at the position (height) $x$, dividing the ice into a lower part $Ilow$   
   > (of height $x$ and mass $m_Ilow (x/L) m_ice$ and an upper part $Ihigh$   
   > (of height $L-x$ and mass $m_Ihigh = (1-x/L) m_ice$.   
      
   Oops, sorry, I was missing an equals sign in the 2nd-to-last line;   
   it should read   
     (of height $x$ and mass $m_Ilow = (x/L) m_ice$ and an upper part $Ihigh$   
      
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   -- "Jonathan Thornburg [remove -color to reply]"    
      (he/him; on the west coast of Canada)   
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