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|    Message 17,492 of 17,516    |
|    Jonathan Thornburg [remove -color t to All    |
|    Re: Tug of War (2/2)    |
|    24 Dec 25 23:28:13    |
      [continued from previous message]               F_son_on_ground - F_father_vs_son = m_son a (23)       i.e.        F_father_vs_son = F_son_on_ground - m_son a (24)       so that by (17)        F_father_vs_son        = F_son_on_ground - (m_son/(m_father+m_son))        (F_son_on_ground - F_father_on_ground) (25)              As a check, (21) and (25) should give the same result: (21) says        F_father_vs_son        = (1 - (m_father/(m_father+m_son)) F_father_on_ground        + (m_father/(m_father+m_son)) F_son_on_ground (26)        = (m_son /(m_father+m_son)) F_father_on_ground        + (m_father/(m_father+m_son)) F_son_on_ground (27)       while (25) says that        F_father_vs_son        = (1 - m_son/(m_father+m_son)) F_son_on_ground        + ( m_son/(m_father+m_son)) F_father_on_ground        = ( m_son/(m_father+m_son)) F_father_on_ground        + (m_father/(m_father+m_son)) F_son_on_ground (29)       and we see that (27) and (29) are in fact identical.                            If the father wants to loose the pull-of-war for a while, this same       analysis still applies with each '>' changed to a '<' and vice versa:       To loose, the father decreases /F_father_on_ground/ so that        F_father_on_ground < F_son_on_ground       and hence by (3) /F_net_on_father_and_son > 0/ and so both people       accelerate to the right (i.e., /a > 0/).                            So, inclusion, now that we look at this system more carefully, we see       that the rope was actually a bit of a distraction. *The actual determinant       of who wins is the balance between how hard the father pushes on the       ground (the force /F_father_on_ground/) versus how hard the son pushes       on the ground (the force /F_son_on_ground/).*              If /F_Father_on_ground = F_son_on_ground/ then the pull-of-war is a       tie, and (7) says that the direct forces /F_father_vs_son/ between father       and son are necessarily equal in magnitude to the forces pushing on the       ground.              If /F_father_on_ground > F_son_on_ground/ then the father wins and       (17) gives the father's and son's acceleration to the left (/a < 0/).       In this case the direct forces /F_father_vs_son/ betwen father and       son have magnitude in between those of the father's and son's forces       on the ground, as given by (14), and in more detail by (27) and (29).              Finally, if /F_father_on_ground < F_son_on_ground/ then the son wins       and (17) gives the father's and son's acceleration to the right (a > 0).       In this case the inequalities in (14) are reversed, and we have        F_father_on_ground < F_father_vs_son < F_son_on_ground (30)       In this case the direct forces /F_father_vs_son/ betwen father and       son still have magnitude in between those of the father's and son's       forces on the ground, and are given (27) and (29).              --       -- "Jonathan Thornburg [remove -color to reply]" |
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