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|    sci.chem    |    Chemistry and related sciences    |    55,615 messages    |
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|    Message 54,032 of 55,615    |
|    Odd Bodkin to Norm X    |
|    Re: the neutron, the nucleus, quarks, an    |
|    05 Mar 17 17:50:11    |
      XPost: sci.physics       From: bodkinodd@gmail.com              On 3/5/2017 5:39 PM, Norm X wrote:       >> An isolated neutron will on average, in its own rest frame, decay into an       >> electron and a proton in less than 15 minutes. The electron is an       >> indivisible particle, while the proton is not.       >>       >> The nucleus of all atoms except hydrogen, is some kind of ensemble of       >> protons and neutron, bound by the strong nuclear force. Isolated protons       >> and neutrons are each identical particles. This may be true even if they       >> are not isolated.       >>       >> According to the standard model, protons and neutron are each some kind of       >> ensemble of quarks, bound by the strong nuclear force.       >>       >> Question: to what extent can we consider the nucleus an ensemble of quarks       >> without recourse to the proton/neutron description of the nucleus?       >>       >> Thanks.       >       > Supplementary question:       >       > Which is better, the proton/neutron description or the quark soup model, for       > prediction of observables, like the scattering diameter of a nucleus? On the       > other hand, are any such observables, useful for refinement of the strong       > nuclear force in the standard model?              Well, as I said, which model is better depends on the energy scale       you're looking at it.              For nuclear interactions, like fission and the like, the energies       involved are around a tenth of the proton mass at most, and so then the       low-energy treatment works just fine. For proton-proton scattering at,       say, the LHC, though, the high-energy treatment works better. At these       latter scales, in fact, the "scattering diameter of the nucleus" becomes       almost irrelevant, because you're really just looking at the scattering       of one quark against another quark, or a gluon against a gluon, or a       gluon against a quark.              The analogy would be if you got two purse-sixed burlap bags, and in each       you put three steel ball bearings. Now put the bags in two launchers and       fire them at each other. If you use slingshots as the launchers, then       you'll see one bag bouncing off another bag, and the rattling around of       the ball bearings inside won't change things much. But if you fired them       out of high-speed cannons, then the impact would most likely be one ball       bearing bouncing off one other ball bearing (the purses being big enough       that it's unlikely that two pairs would collide in the same firing), the       recoiling balls breaking loose from the burlap bags as though they       weren't even there.              >       > Thanks again.       >       >                     --       Odd Bodkin -- maker of fine toys, tools, tables              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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