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|    Message 297,416 of 297,461    |
|    dart200 to olcott    |
|    Re: Proof theoretic semantics based halt    |
|    05 Feb 26 18:49:58    |
   
   XPost: comp.theory, sci.logic, sci.math   
   XPost: comp.lang.prolog, comp.software-eng   
   From: user7160@newsgrouper.org.invalid   
      
   On 2/5/26 12:20 PM, olcott wrote:   
   > On 2/5/2026 12:06 PM, dart200 wrote:   
   >> On 2/4/26 7:04 PM, olcott wrote:   
   >>> On 2/4/2026 8:52 PM, dart200 wrote:   
   >>>> On 2/4/26 6:50 PM, olcott wrote:   
   >>>>> On 2/4/2026 8:42 PM, dart200 wrote:   
   >>>>>> On 2/4/26 4:00 PM, olcott wrote:   
   >>>>>>> On 2/4/2026 5:43 PM, dart200 wrote:   
   >>>>>>>> On 2/4/26 2:27 PM, olcott wrote:   
   >>>>>>>>> On 2/4/2026 4:19 PM, dart200 wrote:   
   >>>>>>>>>> On 2/4/26 2:15 PM, olcott wrote:   
   >>>>>>>>>>> On 2/4/2026 2:41 PM, dart200 wrote:   
   >>>>>>>>>>>> On 2/1/26 9:35 AM, olcott wrote:   
   >>>>>>>>>>>>> On 2/1/2026 6:11 AM, Richard Damon wrote:   
   >>>>>>>>>>>>>> On 1/31/26 12:49 PM, olcott wrote:   
   >>>>>>>>>>>>>>> Source code of fully operational system   
   >>>>>>>>>>>>>>> https://github.com/plolcott/x86utm/blob/master/Halt7.c   
   >>>>>>>>>>>>>>>   
   >>>>>>>>>>>>>>> int DD()   
   >>>>>>>>>>>>>>> {   
   >>>>>>>>>>>>>>> int Halt_Status = HHH(DD);   
   >>>>>>>>>>>>>>> if (Halt_Status)   
   >>>>>>>>>>>>>>> HERE: goto HERE;   
   >>>>>>>>>>>>>>> return Halt_Status;   
   >>>>>>>>>>>>>>> }   
   >>>>>>>>>>>>>>>   
   >>>>>>>>>>>>>>> HHH simulates DD step-by-step according to   
   >>>>>>>>>>>>>>> the semantics of the C programming language.   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> IT CAN'T, as you have been told, as your above program,   
   >>>>>>>>>>>>>> without the C CODE for HHH, has undefined behavior by the   
   >>>>>>>>>>>>>> semantics of the C programming language.   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> HHH as executed by polcott is exhibiting a classifier   
   >>>>>>>>>>>> interface i'm calling a *partial recognizer*   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> (machine) -> {   
   >>>>>>>>>>>> TRUE iff machine HALTS and DECIDABLE,   
   >>>>>>>>>>>> FALSE iff machine LOOPS or UNDECIDABLE,   
   >>>>>>>>>>>> }   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> it doesn't do so quite so intelligently, but HHH(DD) needs   
   >>>>>>>>>>>> to return FALSE because DD is an UNDECIDABLE input to HHH   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> polcott does this by detecting the infinite recursion and   
   >>>>>>>>>>>> returning FALSE because of that   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> this approach of returning FALSE upon encountering an   
   >>>>>>>>>>>> infinite recursion on self (which i believe all paradoxes   
   >>>>>>>>>>>> will involve) will either be accurate or inaccurate in   
   >>>>>>>>>>>> regards to actually halting/ not... but it doesn't matter   
   >>>>>>>>>>>> because returning FALSE for halting yet UNDECIDABLE input is   
   >>>>>>>>>>>> acceptable for a *partial recognizer*   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> where this wouldn't work is:   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> int ND()   
   >>>>>>>>>>>> {   
   >>>>>>>>>>>> int Halt_Status = HHH(ND);   
   >>>>>>>>>>>> return Halt_Status;   
   >>>>>>>>>>>> }   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> HHH(ND) -> FALSE because HHH(ND) will recognize the infinite   
   >>>>>>>>>>>> recursion and return FALSE ... but that's not an acceptable   
   >>>>>>>>>>>> response for a *partial recognizer* for ND because ND is not   
   >>>>>>>>>>>> an UNDECIDABLE input, and it clearly should HALT   
   >>>>>>>>>>>>   
   >>>>>>>>>>>> sorry polcott   
   >>>>>>>>>>>>   
   >>>>>>>>>>>   
   >>>>>>>>>>> That is merely a text message that has not been updated.   
   >>>>>>>>>>>   
   >>>>>>>>>>> See my other post:   
   >>>>>>>>>>> When halt provers are allowed to reject bad   
   >>>>>>>>>>> inputs the remaining domain is decidable   
   >>>>>>>>>>>   
   >>>>>>>>>>> A bad input is any input that does not have   
   >>>>>>>>>>> *a well-founded justification tree within Proof*   
   >>>>>>>>>>> *theoretic semantics*   
   >>>>>>>>>>>   
   >>>>>>>>>>> For a simulating halt prover as soon as it detects   
   >>>>>>>>>>> that its simulated input cannot possibly reach its   
   >>>>>>>>>>> own simulated final halt state for any reason   
   >>>>>>>>>>> what-so-ever then this input
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