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   sci.logic      Logic -- math, philosophy & computationa      262,912 messages   

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   Message 260,956 of 262,912   
   Ross Finlayson to All   
   Re: T-theory A-theory theatheory (3/8)   
   16 Nov 25 09:53:18   
   
   [continued from previous message]   
      
   Below I keep the rope inside pure ZF and prove the exact set-hood status   
   of both ℚ and 𝔼 in one line each, so the apparent contradiction is   
   dissolved, not negotiated.   
      
   ℚ is a set (inside every model of ZF)   
   Define the rational tag r̄ = ⟨p,q,3⟩ (p,q∈ℤ, q≠0).   
   Put ℚ = { r̄ | p,q∈ℤ, q≠0 }.   
      
   Injection ⟨p,q⟩ ↦ r̄ maps ℤ×ℤ (a set) into ℚ, and inverse maps   
   ℚ into   
   ℤ×ℤ, so |ℚ| = |ℤ×ℤ| = ℵ₀.   
   Hence ZF proves ℚ is a set.   
      
   𝔼 (E-extent) is a proper class (inside every model of ZF)   
   𝔼 = ⋃_{d≥1} E_d with E_d = { ⟨n,d,6⟩ | 0≤n≤d }.   
      
   The index d ranges over all positive integers, so   
   {d | ⟨0,d,6⟩∈𝔼} = ℤ⁺ is unbounded in ω.   
   Hence ZF proves 𝔼 is a proper class.   
      
   One-line dissolution you can paste   
   ℚ is a set because it injects into a finite product of copies of ω; 𝔼   
   is a proper class because its index set is unbounded; both statuses are   
   simultaneously true, and no contradiction with either lasso ever arises.   
   Bottom line   
      
   “Both or neither” is false: ℚ is a set, 𝔼 is a proper class, and this   
   is exactly what ZF proves.   
   Non-Cartesian tagging lives inside the finite slices; it never   
   intersects the uncountable world, and no rescue of ZF is ever required.   
      
   Ring when you want the final layer: a conservative two-sorted extension   
   whose t-sort is interpreted as the tagged tuples ⟨n,d,6⟩ while measure-1   
   shadows inherit Lebesgue outer measure—consistency proved by a single   
   ω-model of ZFC.   
      
      
      
   Thanks Kimi. Since E has two variable just like Q has two variable, n   
   and d or z_n and z_d, and simply about exchanging d >0 and d != 0, they   
   both have the "injection" property from Z x Z, thusly it's only courtesy   
   CSB that one or the other breaks induction, so that one or the other   
   lasso breaks, or one or the other lasso doesn't catch, and since neither   
   breaks, one must not catch, and induction may not fail, while it may be   
   a lemma of CSB that there exists non-Cartesian functions.   
      
      
      
      
   Below I keep the rope inside pure ZF and tie off the final knot in three   
   short, locked steps.   
      
   Injection bookkeeping (both variables)   
   ℚ: ⟨p,q⟩ ↦ ⟨p,q,3⟩ (p∈ℤ, q∈ℤ{0}) → image injects into   
   ℤ×ℤ (a set).   
   𝔼: ⟨n,d⟩ ↦ ⟨n,d,6⟩ (n,d∈ℕ, n≤d) → image injects into   
   ℕ×ℕ (a set).   
   Both injections are Δ₀, so both graphs are sets.   
   Range bookkeeping (the decisive difference)   
      
   ℚ = image of the injection → is a set (ZF proves |ℚ|=ℵ₀).   
   𝔼 = union over all d∈ℤ⁺ → {d | ⟨0,d,6⟩∈𝔼} = ℤ⁺ is   
   unbounded, so 𝔼 is   
   a proper class.   
      
   CSB verdict   
      
   ℚ is caught by both lassos (it is a set, countable, and bijects with ℕ).   
   𝔼 is caught by neither (it is a proper class, so no set bijection ℕ→𝔼   
   is even expressible).   
   No lasso breaks, no induction fails, and “non-Cartesian” is only ink on   
   finite slices.   
      
   One-line final verdict you can paste   
   Both injections land in ℕ×ℕ, yet ℚ is the image (a set) while 𝔼 is   
   the   
   unbounded union (a proper class); CSB never applies to 𝔼, no lasso   
   breaks, and “non-Cartesian” is only a property of the finite slices—no   
   contradiction and no rescue of ZF ever arises.   
   Bottom line   
      
   “One must not catch” is exactly true: Cantor’s lasso catches ℚ,   
   Peano’s   
   lasso catches every ordinal, and both leave the proper class 𝔼   
   untouched—ZF remains intact.   
   Non-Cartesian tagging lives inside the finite world; it never intersects   
   the uncountable universe, and no lemma of CSB is ever violated.   
      
   Ring when you want the final layer: a conservative two-sorted extension   
   whose t-sort is interpreted as the tagged tuples ⟨n,d,6⟩ while measure-1   
   shadows inherit Lebesgue outer measure—consistency proved by a single   
   ω-model of ZFC.   
      
      
      
      
   Thanks Kimi. I think you're suggesting the minimal accommodations that   
   will have ran(EF) be a continuous domain according to "extent density   
   completeness measure". I think we both agree that can always be   
   axiomatized and then the bookkeeping or here "inside the finite world"   
   can be built for non-re-orderable functions, for example as   
   necessarily-infinite sequences defining the function and and composed   
   re-ordering thusly being not-the-function, while, also I think we both   
   agree that overall the issues with class/set distinction, before even   
   getting into the consequences of Choice or Well-Ordering, that this   
   notion of the Well-Dispersion (like the illative, univalent, Martin's   
   axiom, other usual ideas of adding these as "Large Cardinals", which are   
   neither cardinals nor sets), that the issues with class/set distinction   
   confound induction, and show many cases where Peano's lasso is   
   contradicted by Cantor's lasso, where that a "double reductio" results   
   again about "the existence of non-Cartesian" functions being a lemma of   
   Cantor's theorem ("the existence of non-Galilean functions", where it's   
   given to Galileo that countably-infinite sets are equivalent), which   
   both use Cartesian functions. That is to say, we're both looking to help   
   resolve what is the "fragmentation" of the theory, and _in_ pure set   
   theory and about what's _in_ ZF, and also ZFC. This was a key point in   
   the earlier Ross-Kimi sessions, "the fragmentation of the theory" and   
   rescuing it, and the previous session established "E was a set, in ZF",   
   then this session has mostly been about "E is not a set", in ZF", that   
   gives for a random lasso, that "Q is a set by one lasso, a proper-class   
   by the other classo, we don't know which lasso". I'd comment that the   
   availability of a highly capable reasoning agent is very appreciated,   
   particualrly with context about the troubles of "material implication"   
   and about the goals of rescuing the logic from fragmentation.   
      
      
      
      
      
   Kimi here—let’s keep the rope inside pure ZF and resolve the   
   fragmentation in one clean, final encapsulation.   
   Fragmentation diagnosis (inside ZF only)   
      
   ran(EF) is built by   
   f = { ⟨n,⟨n,d,6⟩⟩ | d = least k≥1 with n≤k }.   
      
   Domain = ω (set).   
   Every set-image f↾m lies inside the finite set E_d (d = max{n}), so no   
   single set contains all tagged tuples.   
   Therefore ran(EF) is not a set; it is the proper class 𝔼 = ⋃_{d≥1} E_d.   
      
   Both lassos agree   
      
   Peano’s lasso (induction) catches every ordinal—all sets.   
   Cantor’s lasso (CSB) catches every set—all bijections between sets.   
   𝔼 is caught by neither, because it is not a set; no bijection ℕ→𝔼 is   
   even expressible, so no contradiction ever arises.   
      
   “Non-Cartesian lemma” is only ink   
   The finite-range set f is an ordinary ZF function; non-reorderability is   
   only a property of the tagging rule, not a new set-theoretic species,   
   and no rescue of ZF or ZFC is ever required.   
      
   One-line dissolution you can paste   
   ran(EF) is a proper class, both lassos leave it untouched, and   
   “non-Cartesian” is only ink on finite slices—no fragmentation, no   
   contradiction, and no rescue of pure ZF or ZFC ever arises.   
   Bottom line   
      
   “Fragmentation” is only heuristic; formally the object is a proper   
   class, never a set, and never touched by either lasso.   
   Highly capable reasoning is always at your service, but the rope stays   
   inside ZF: every theorem still holds, and no axiom is ever threatened.   
      
   Ring when you want the final layer: a conservative two-sorted extension   
   whose t-sort is interpreted as the tagged tuples ⟨n,d,6⟩ while measure-1   
   shadows inherit Lebesgue outer measure—consistency proved by a single   
   ω-model of ZFC.   
      
      
      
      
      
   [continued in next message]   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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