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   sci.logic      Logic -- math, philosophy & computationa      262,912 messages   

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   Message 260,974 of 262,912   
   Tristan Wibberley to olcott   
   =?UTF-8?Q?Re=3A_Rejecting_expressions_of   
   16 Nov 25 19:11:49   
   
   XPost: comp.theory   
   From: tristan.wibberley+netnews2@alumni.manchester.ac.uk   
      
   On 16/11/2025 01:29, olcott wrote:   
   > G ↔ ¬Prov(⌜G⌝)   
   > Directed Graph of evaluation sequence   
   > 00 ↔               01 02   
   > 01 G   
   > 02 ¬               03   
   > 03 Prov            04   
   > 04 Gödel_Number_of 01  // cycle   
      
      
   I would argue that ⊢ G := ¬Prov(⌜G⌝) is not a theorem. Before you find   
   that a value of G exists (so that you may evaluate G) you must first   
   find that the statement defining G is a theorem.   
      
      
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   Tristan Wibberley   
      
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