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|    Message 261,721 of 262,912    |
|    olcott to Mikko    |
|    Re: A new foundation for correct reasoni    |
|    06 Dec 25 06:50:22    |
      XPost: comp.theory, sci.math, comp.lang.prolog       From: polcott333@gmail.com              On 12/6/2025 3:30 AM, Mikko wrote:       > olcott kirjoitti 5.12.2025 klo 19.43:       >> On 12/5/2025 3:38 AM, Mikko wrote:       >>> olcott kirjoitti 4.12.2025 klo 16.06:       >>>> On 12/4/2025 2:58 AM, Mikko wrote:       >>>>> Tristan Wibberley kirjoitti 4.12.2025 klo 4.32:       >>>>>> On 30/11/2025 09:58, Mikko wrote:       >>>>>>       >>>>>>> Note that the meanings of       >>>>>>> ?- G = not(provable(F, G)).       >>>>>>> and       >>>>>>> ?- unify_with_occurs_check(G, not(provable(F, G))).       >>>>>>> are different. The former assigns a value to G, the latter does not.       >>>>>       >>>>>> For sufficiently informal definitions of "value".       >>>>>> And for sufficiently wrong ones too!       >>>>>       >>>>> It is sufficiently clear what "value" of a Prolog variable means.       >>>       >>>> % This sentence cannot be proven in F       >>>> ?- G = not(provable(F, G)).       >>>> G = not(provable(F, G)).       >>>> ?- unify_with_occurs_check(G, not(provable(F, G))).       >>>> false.       >>>>       >>>> I would say that the above Prolog is the 100%       >>>> complete formal specification of:       >>>>       >>>> "This sentence cannot be proven in F"       >>>       >>> The first query can be regarded as a question whether "G = not(provable(       >>> F, G))" can be proven for some F and some G. The answer is that it can       >>> for every F and for (at least) one G, which is not(provable(G)).       >>>       >>> The second query can be regarded as a question whether "G = not(provable       >>> (F, G))" can be proven for some F and some G that do not contain cycles.       >>> The answer is that in the proof system of Prolog it cannot be.       >>>       >>       >> No that it flatly incorrect. The second question is this:       >> Is "G = not(provable(F, G))." semantically sound?       >       > When "G = not(provable(F, G))." is used as a Prolog goal the       > applied semantics is what Prolog lauguage definition specifies.       > Does "semantically sound" mean something in that context?       >       > At least your Prolog interpretation finds it meaningful. It determines       > that the excution of that goal succeeds and assigns a value G but not       > to F.       >              Is this sentence true or false:       "This sentence is not true"       It is not semantically sound.              Is this sentence true or false:       "This sentence cannot be proved"       It is not semantically sound.                     --       Copyright 2025 Olcott              My 28 year goal has been to make       "true on the basis of meaning" computable.              This required establishing a new foundation       for correct reasoning.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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