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|    Message 262,303 of 262,912    |
|    olcott to olcott    |
|    Re: have we been misusing incompleteness    |
|    01 Jan 26 21:26:55    |
      XPost: comp.theory, sci.math       From: polcott333@gmail.com              On 1/1/2026 8:38 PM, olcott wrote:       > On 1/1/2026 8:25 PM, Richard Damon wrote:       >> On 1/1/26 9:07 PM, olcott wrote:       >>> On 1/1/2026 4:12 PM, Tristan Wibberley wrote:       >>>> On 31/12/2025 23:27, Richard Damon wrote:       >>>>       >>>>> So, how do you think you can prove it in F?       >>>>       >>>> What does "F" refer to?       >>>>       >>>       >>> F ⊢ G_F ↔ ¬Prov_F(⌜G_F⌝)       >>> F proves that: G_F is equivalent to G_F is not provable in F       >>> https://plato.stanford.edu/entries/goedel-incompleteness/#FirIncTheCom       >>>       >>> ∃G ∈ WFF(F) (G ↔ (F ⊬ G))       >>> There exists a G in F that is logically       >>> equivalent to its own unprovability in F       >>>       >>> ∃G ∈ WFF(F) (G := (F ⊬ G))       >>> There exists a G in F that asserts its own unprovability in F       >>>       >>> The proof of G in F would seem to require a sequence       >>> of inference steps in F that prove that they themselves       >>> do not exist.       >>>       >>>       >>       >> But that isn't what G is in the proof, so you are just using a bad       >> reference.       >>       >       > That you do not know exactly how semantics works in       > linguistics (making sure to ignore all context) is       > not my mistake. The reason that Ludwig Wittgenstein       > was never understood is that none of his detractors       > understood how language itself really works. Not       > knowing how language really works results in       > undetected muddled thinking.       >       > ...We are therefore confronted with a proposition which       > asserts its own unprovability. 15 … (Gödel 1931:40-41)       >       > G asserts its own unprovability.       > Is what the above means semantically.       >       > The proof of G does semantically entail a sequence       > of inference steps that prove that they themselves       > do not exist.       >              Ludwig Wittgenstein              8. I imagine someone asking my advice; he says:       "I have constructed a proposition (1 will use       'P' to designate it) in Russell's symbolism,       and by means of certain definitions and       transformations it can be so interpreted that       it says: 'P is not provable in Russell's system'.                     Must I not say that this proposition on the one       hand is true, and on the other hand is unprovable?       For suppose it were false; then it is true that       it is provable. And that surely cannot be And       if it is proved, then it is proved that it is       not provable. Thus it can only be true, but       unprovable. " Just as we ask: " 'provable'       in what system?", so we must also ask:"       'true' in what system?" 'True in Russell's system'       means, as was said: proved in Russell's system;       and 'false in Russell's system' means: the       opposite has been proved in Russell's system              --       Copyright 2025 Olcott |
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