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|    Message 262,811 of 262,912    |
|    dart200 to olcott    |
|    Re: Proof theoretic semantics based halt    |
|    05 Feb 26 19:23:50    |
   
   XPost: comp.theory, sci.math, comp.lang.prolog   
   XPost: sci.lang, comp.software-eng   
   From: user7160@newsgrouper.org.invalid   
      
   On 2/5/26 7:11 PM, olcott wrote:   
   > On 2/5/2026 8:49 PM, dart200 wrote:   
   >> On 2/5/26 12:20 PM, olcott wrote:   
   >>> On 2/5/2026 12:06 PM, dart200 wrote:   
   >>>> On 2/4/26 7:04 PM, olcott wrote:   
   >>>>> On 2/4/2026 8:52 PM, dart200 wrote:   
   >>>>>> On 2/4/26 6:50 PM, olcott wrote:   
   >>>>>>> On 2/4/2026 8:42 PM, dart200 wrote:   
   >>>>>>>> On 2/4/26 4:00 PM, olcott wrote:   
   >>>>>>>>> On 2/4/2026 5:43 PM, dart200 wrote:   
   >>>>>>>>>> On 2/4/26 2:27 PM, olcott wrote:   
   >>>>>>>>>>> On 2/4/2026 4:19 PM, dart200 wrote:   
   >>>>>>>>>>>> On 2/4/26 2:15 PM, olcott wrote:   
   >>>>>>>>>>>>> On 2/4/2026 2:41 PM, dart200 wrote:   
   >>>>>>>>>>>>>> On 2/1/26 9:35 AM, olcott wrote:   
   >>>>>>>>>>>>>>> On 2/1/2026 6:11 AM, Richard Damon wrote:   
   >>>>>>>>>>>>>>>> On 1/31/26 12:49 PM, olcott wrote:   
   >>>>>>>>>>>>>>>>> Source code of fully operational system   
   >>>>>>>>>>>>>>>>> https://github.com/plolcott/x86utm/blob/master/Halt7.c   
   >>>>>>>>>>>>>>>>>   
   >>>>>>>>>>>>>>>>> int DD()   
   >>>>>>>>>>>>>>>>> {   
   >>>>>>>>>>>>>>>>> int Halt_Status = HHH(DD);   
   >>>>>>>>>>>>>>>>> if (Halt_Status)   
   >>>>>>>>>>>>>>>>> HERE: goto HERE;   
   >>>>>>>>>>>>>>>>> return Halt_Status;   
   >>>>>>>>>>>>>>>>> }   
   >>>>>>>>>>>>>>>>>   
   >>>>>>>>>>>>>>>>> HHH simulates DD step-by-step according to   
   >>>>>>>>>>>>>>>>> the semantics of the C programming language.   
   >>>>>>>>>>>>>>>>   
   >>>>>>>>>>>>>>>> IT CAN'T, as you have been told, as your above program,   
   >>>>>>>>>>>>>>>> without the C CODE for HHH, has undefined behavior by   
   >>>>>>>>>>>>>>>> the semantics of the C programming language.   
   >>>>>>>>>>>>>>>>   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> HHH as executed by polcott is exhibiting a classifier   
   >>>>>>>>>>>>>> interface i'm calling a *partial recognizer*   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> (machine) -> {   
   >>>>>>>>>>>>>> TRUE iff machine HALTS and DECIDABLE,   
   >>>>>>>>>>>>>> FALSE iff machine LOOPS or UNDECIDABLE,   
   >>>>>>>>>>>>>> }   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> it doesn't do so quite so intelligently, but HHH(DD) needs   
   >>>>>>>>>>>>>> to return FALSE because DD is an UNDECIDABLE input to HHH   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> polcott does this by detecting the infinite recursion and   
   >>>>>>>>>>>>>> returning FALSE because of that   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> this approach of returning FALSE upon encountering an   
   >>>>>>>>>>>>>> infinite recursion on self (which i believe all paradoxes   
   >>>>>>>>>>>>>> will involve) will either be accurate or inaccurate in   
   >>>>>>>>>>>>>> regards to actually halting/ not... but it doesn't matter   
   >>>>>>>>>>>>>> because returning FALSE for halting yet UNDECIDABLE input   
   >>>>>>>>>>>>>> is acceptable for a *partial recognizer*   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> where this wouldn't work is:   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> int ND()   
   >>>>>>>>>>>>>> {   
   >>>>>>>>>>>>>> int Halt_Status = HHH(ND);   
   >>>>>>>>>>>>>> return Halt_Status;   
   >>>>>>>>>>>>>> }   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> HHH(ND) -> FALSE because HHH(ND) will recognize the   
   >>>>>>>>>>>>>> infinite recursion and return FALSE ... but that's not an   
   >>>>>>>>>>>>>> acceptable response for a *partial recognizer* for ND   
   >>>>>>>>>>>>>> because ND is not an UNDECIDABLE input, and it clearly   
   >>>>>>>>>>>>>> should HALT   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>> sorry polcott   
   >>>>>>>>>>>>>>   
   >>>>>>>>>>>>>   
   >>>>>>>>>>>>> That is merely a text message that has not been updated.   
   >>>>>>>>>>>>>   
   >>>>>>>>>>>>> See my other post:   
   >>>>>>>>>>>>> When halt provers are allowed to reject bad   
   >>>>>>>>>>>>> inputs the remaining domain is decidable   
   >>>>>>>>>>>>>   
   >>>>>>>>>>>>> A bad input is any input that does not have   
   >>>>>>>>>>>>> *a well-founded justification tree within Proof*   
   >>>>>>>>>>>>> *theoretic semantics*   
   >>>>>>>>>>>>>   
   >>>>>>>>>>>>> For a simulating halt prover as soon as it detects   
   >>>>>>>>>>>>> that its simulated input cannot possibly reach its   
   >>>>>>>>>>>>> own simulated final halt state for any reason   
   >>>>>>>>>>>>> what-so-ever then this input
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