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|    sci.physics.relativity    |    The theory of relativity    |    225,861 messages    |
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|    Message 224,970 of 225,861    |
|    Vittorio Dubasov to All    |
|    Re: Acting forces    |
|    28 Nov 25 12:17:32    |
      XPost: sci.math       From: ivvu@tor.ru              Jonathan Thornburg [remove -color to reply]" wrote:              > F_net_on_m1 = F1 + F3 = 100-95 = +5 F_net_on_m2 = -F3 - F4 = -(-95) -       > (55) = 95-55 = +40 F_net_on_m3 = F2 + F4 = -50 +55 = +5       > The forces are now different from the equal-mass case (which is not       > surprising, since we've changed the mass of each individual body).       > Notice that the forces are in the ratio       > F_net_on_m1 = F_net_on_m3 = (1/8) F_net_on_m2       > which just match the ratios of the masses,       > m1 = m3 = (1/8) m2       > This is just what we would expect from Newton's 2nd law, since all all       > three masses have the same common acceleration.       >       > So, the simple answer to Luigi's questions is "it depends on the body's       > internal mass distribution".              then you didn't yet got into the internal and external curvatures,       especially regarding large masses              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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