From: relativity@paulba.no   
      
   Den 22.01.2026 18:13, skrev Ross Finlayson:   
   > On 01/22/2026 06:12 AM, Paul B. Andersen wrote:   
   >> Den 21.01.2026 18:11, skrev Ross Finlayson:   
   >>> On 01/21/2026 06:05 AM, Paul B. Andersen wrote:   
   >>>> Den 20.01.2026 19:35, skrev Ross Finlayson:   
   >>>>> On 01/20/2026 05:54 AM, Paul B. Andersen wrote:   
   >>>>>>   
   >>>>>> You are standing on the floor in a small room   
   >>>>>> without windows with an accelerometer fixed to the wall.   
   >>>>>> The accelerometer shows that it is accelerating   
   >>>>>> in the direction which to you is upwards.   
   >>>>>>   
   >>>>>> If the accelerometer shows that the acceleration   
   >>>>>> is constant 1g, then there is no way you can   
   >>>>>> decide whether you are stationary at the ground,   
   >>>>>> or if you are accelerating at 1g in a spaceship.   
   >>>>>>   
   >>>>>> If the accelerometer shows that the acceleration   
   >>>>>> is changing with time, then you know that you are   
   >>>>>> in a spaceship.   
   >>>>>>   
   >>>>   
   >>>> The following is obviously not a response to my post above.   
   >>>>   
   >>>>>   
   >>>>> As the elevator rises, according to inverse square,   
   >>>>> either the force is constant or acceleration is constant,   
   >>>>> not both.  I.e. the force decreases or acceleration   
   >>>>> increases as the elevator rises, since distance increases.   
   >>>>   
   >>   
   >> You said:   
   >> "Either the force is constant or acceleration is constant,   
   >>   not both."   
   >>   
   >> That can only mean that the acceleration is not constant   
   >> if the force is constant.   
   >>   
   >> Hence my question:   
   >>   
   >>>> Are you trying to say that if the force on an object   
   >>>> is constant, then its proper acceleration is not constant?   
   >>>>   
   >>>> < snip>   
   >>>>   
   >>>   
   >>> The gradient of gravitational force, often enough about   
   >>> its "depth" in the "well" of gravity, or about however   
   >>> it's so in GR between the space with the Euclidean metric   
   >>> and however it's so in the space of a body its Riemannian   
   >>> metric, has that since force is proportional to inverse   
   >>> square of distance, as distance changes, force changes.   
   >>>   
   >>> Then, "the measured acceleration", changes, yes.   
   >>   
   >> So now you say: "If force changes, acceleration changes."   
   >>   
   >> But that does not answer my question, which   
   >> slightly reformulated is:   
   >> "If the force is constant, is then the proper   
   >>   acceleration constant?"   
   >>   
   >> Can you answer yes or no, please?   
   >>   
   >>   
   >   
   > It would be easier if it were so,   
   > yet, there are two inductive accounts   
   > that don't agree.   
      
   ..but it isn't "so" that if the force is constant,   
      then the proper acceleration is constant.   
      
   Your answer is "no".   
      
   Thanks!   
      
      
   --   
   Paul   
      
   https://paulba.no/   
      
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