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|    sci.physics.relativity    |    The theory of relativity    |    225,861 messages    |
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|    Message 225,405 of 225,861    |
|    Jassen Tzekhanovich to Ross Finlayson    |
|    Re: Gravitational acceleration    |
|    26 Jan 26 17:28:10    |
      XPost: sci.math       From: ivsks@na.ru              Ross Finlayson wrote:              > rest/rest motion/motion equal/opposite <- isn't that three laws?       > F = ma <- that's also F(t) = m d^2 x /dt^2, differential d              finally a one that can read. And when you have no spatial change, that       force is zero? Can you see now why that's a constant, named g, and not an       acceleration. Tell it to your friend pointedhead, what a waste of time              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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