From: ttt_heg@web.de   
      
   Am Montag000026, 26.01.2026 um 13:40 schrieb Paul B. Andersen:   
   > Den 25.01.2026 22:15, skrev Maciej Woźniak:   
   >> On 1/25/2026 7:59 PM, Paul B. Andersen wrote:   
   >>> Den 24.01.2026 13:08, skrev Maciej Woźniak:   
   >>>> On 1/24/2026 12:34 PM, Paul B. Andersen wrote:   
   >>>>> Den 24.01.2026 07:51, skrev Maciej Woźniak:   
   >>>>>> On 1/23/2026 8:32 PM, Paul B. Andersen wrote:   
   >>>>>>> Den 22.01.2026 22:31, skrev Maciej Woźniak:   
   >>>>>>>> On 1/22/2026 9:57 PM, Paul B. Andersen wrote:   
   >>>>>>>>>   
   >>>>>>>>> Let us look at a concrete example.   
   >>>>>>>>> The length of the string is L = 1.4142 m, and the mass m is 1 kg.   
   >>>>>>>>> You swing the object such that it takes t = two seconds to make   
   >>>>>>>>> a full turn.   
   >>>>>>>>> You observe that the angle of the string to the ground is 45⁰.   
   >>>>>>>>> That means that the radius of the circle the object is moving   
   >>>>>>>>> along is:   
   >>>>>>>>>   r = L/√(2) = 1 m   
   >>>>>>>>> It is then easy to calculate that the speed of the object is   
   >>>>>>>>>   v = 2⋅π⋅r/t = 3.14 m/s   
   >>>>>>>>> The horizontal centripetal acceleration is:   
   >>>>>>>>>   aₕ = v²/r = 9.8 m/s²  (towards centre of circle)   
   >>>>>>>>> The horizontal component of the tension in the string is:   
   >>>>>>>>>   Fₕ = m⋅aₕ = 9.8 N   
   >>>>>>>>> Since the angle of the string to the ground is 45⁰, the vertical   
   >>>>>>>>> component of of the tension in the string is:   
   >>>>>>>>>   Fᵥ = Fₕ   
   >>>>>>>   
   >>>>>>> The vertical component of the force acting on the object is:   
   >>>>>>>    Fᵥ = 9.8 N  (constant upwards)   
   >   
   >>>>>> So what?   
   >   
   >>>>> Do you have a reading comprehension problem?   
   >>>>>   
   >>>>> So according to Newton's law F = ma the acceleration   
   >>>>> of the object is a = F/m = 9.8 m/s²  (upwards)   
   >   
   >>>> Do you have a reading comprehension problem,   
   >>>> poor trash?   
   >>>> Of course you do, otherwise you would know   
   >>>> that Newton's law is  for unbalanced (or,   
   >>>> if you prefer, net) force.   
   >   
   >>> The net vertical component of the force acting on   
   >>> the object is:  Fᵥ = 9.8 N  (constant upwards)   
   >   
   >> If it was, poor trash - the object would   
   >> accelerate upward. It doesn't, the vertical   
   >> component of velocity is constant and 0.   
   >> Sorry, poor trash.   
   >   
   > Why do you pretend to be an idiot?   
   >   
   > You _know_ that the string is pulling the object   
   > with mass 1 kg with a force F = 9.8 N upwards.   
   > If it were not, the object would be in free fall.   
   >   
   > So why do you claim that this upwards force doesn't exist?   
   >   
   > You do understand that the force the chair is   
   > acting on your butt is upwards, don't you?   
   > Or don't you?   
   >   
   >>> You can feel the net force acting on _you_   
   >>> right now, and you can measure it precisely.   
   >>> If you sit on a weight, you can measure the net   
   >>> force the weight is acting on your butt.   
   >>> It will be F = 9.8⋅m N  where m is your mass.   
   >>> This upwards force is the net unbalanced force.   
   >>> If the force were balanced it would be zero,   
   >>> and the weight would show that you were weightless.   
   >>>   
   >>> The force pushing your butt will give you a proper   
   >>> acceleration 9.8 m/s² upwards.   
   >> Stop mumbling and learn some basic physics,   
   >   
   > You mean I should learn that the law F = ma is invalid   
   > if F is a vertical force?   
   >   
   That 'F' in connection with gravity is usually called 'weight'.   
      
   That is the force, by which a material object pushes against the   
   surface, upon which it stands (or sits).   
      
   That 'a' has (on planet Earth) a numerical value of roughly 9.81 m/s²   
      
   The weight is measured in Newtons, while mass is measured in kg.   
      
   Now the force in this picture is NOT gravity, but weight.   
      
   And, yes, weight operates vertically.   
      
   TH   
      
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