04333834   
   From: relativity@paulba.no   
      
   Den 28.01.2026 21:02, skrev Maciej Woźniak:   
   > On 1/28/2026 8:04 PM, Paul B. Andersen wrote:   
   >> Den 28.01.2026 07:56, skrev Maciej Woźniak:   
      
   >>>   
   >>> BTW. You wrote:   
   >>>   
   >>> 1)an object is always at rest (velocity 0)   
   >>> in its rest frame   
   >>> 2)proper acceleration of an object is its   
   >>> acceleration  measured  in its rest frame   
   >>>   
   >>> 1+2=3) the proper acceleration of any   
   >>> object is always 0.   
   >>> Sorry, poor trash.   
   >> Now I know that you still think that if a spacecraft   
   >> with mass 1000 kg is pushed by a rocket engine with   
   >> the force F = 10000 N, then the proper acceleration of   
   >> the spacecraft is a = 0  because the speed of the spacecraft   
   >> relative to itself is 0 m/s.   
      
   >   
   > Sure, and a proper shark eats grass.   
   >   
   > Still, 1+2=3. According to the definition   
   > you've invented  the proper acceleration of   
   > any object is always 0. Sorry, poor trash.   
      
   :-D   
      
   Given v(t) = kt where k is a constant, -∞ < t < ∞   
      
   What is v at t = 0?   
   What is dv/dt at t = 0?   
      
   Still not got it?   
      
   --   
   Paul   
      
   https://paulba.no/   
      
   --- SoupGate-Win32 v1.05   
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