From: nospam@de-ster.demon.nl   
      
   Thomas 'PointedEars' Lahn  wrote:   
      
   > Thomas 'PointedEars' Lahn wrote:   
   > > For example, if the quantum-electromagnetic field has an energy that is ? f   
   > > (or ? c/?, or ? k c) above its ground-state energy (which is also its zero-   
   > > point energy), then we say that there is a photon with frequency f (or   
   > > wavelength ?, or wavenumber k, respectively): the photon is the quantum of   
   > > that field (AISB).   
   >   
   > Sorry, that's   
   >   
   >   E = p c = _?_ k c = ?/(2π) (2π/?) c = ? c/? = ? f.   
      
   Great formula!   
      
   Jan   
      
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